Chapter 3: Problem 22
Which of the following is not a possible zero of $$ \begin{aligned} f(x)=4 x^{5}-2 x^{3}+& 10 ? \\ 3,5, \frac{5}{2}, \frac{3}{2} \end{aligned} $$
Short Answer
Expert verified
None of the candidates 3, 5, \( \frac{5}{2} \), \( \frac{3}{2} \) are zeros.
Step by step solution
01
- Define the Polynomial
The given polynomial is \[ f(x) = 4x^5 - 2x^3 + 10 \].
02
- Understand Zero of Polynomial
A number c is a zero of the polynomial f(x) if \[ f(c) = 0 \].
03
- Evaluate f(x) at Each Given Zero Candidate
We need to substitute each candidate into f(x) and determine if the result is zero. The candidates are 3, 5, \( \frac{5}{2} \), and \( \frac{3}{2} \).
04
- Calculate f(3)
Evaluate \[ f(3) = 4(3)^5 - 2(3)^3 + 10 = 4 \cdot 243 - 2 \cdot 27 + 10 = 972 - 54 + 10 = 928 \]. Since 928 ≠0, 3 is not a zero.
05
- Calculate f(5)
Evaluate \[ f(5) = 4(5)^5 - 2(5)^3 + 10 = 4 \cdot 3125 - 2 \cdot 125 + 10 = 12500 - 250 + 10 = 12260 \]. Since 12260 ≠0, 5 is not a zero.
06
- Calculate f( \frac{5}{2} )
Evaluate \[ f( \frac{5}{2} ) = 4 ( \frac{5}{2} )^5 - 2 ( \frac{5}{2} )^3 + 10 = 4 \cdot \frac{3125}{32} - 2 \cdot \frac{125}{8} +10 = \frac{12500}{32} - \frac{250}{8} + 10 = \frac{12500}{32} - \frac{1000}{32} + 10 = \frac{11500}{32} + 10 \approx 368.75 \]. Since 368.75 ≠0, \( \frac{5}{2} \) is not a zero.
07
- Calculate f( \frac{3}{2} )
Evaluate \[ f( \frac{3}{2} ) = 4 ( \frac{3}{2} )^5 - 2 ( \frac{3}{2} )^3 + 10 = 4 \cdot \frac{243}{32} - 2 \cdot \frac{27}{8} + 10 = \frac{972}{32} - \frac{54}{8} + 10 = \frac{972}{32} - \frac{216}{32} + 10 = \frac{756}{32} + 10 \approx 23.625 \]. Since 23.625 ≠0, \( \frac{3}{2} \) is not a zero.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
evaluating polynomials
To understand whether a number is a zero of a polynomial, we start by evaluating the polynomial at that number. Evaluating a polynomial means to substitute a given value for the variable and simplify it. For example, if we have a polynomial \( f(x) = 4x^5 - 2x^3 + 10 \) and want to evaluate it at \( x = 3 \), we substitute 3 for x:
- First, compute \( 4 \times 3^5 \). Since \( 3^5 = 243 \), we have \( 4 \times 243 = 972 \).
- Next, compute \( -2 \times 3^3 \). Since \( 3^3 = 27 \), we have \( -2 \times 27 = -54 \).
- Finally, add 10: \( 972 - 54 + 10 = 928 \).
zero of a polynomial
A zero of a polynomial is a value of x for which the polynomial equals zero. Mathematically, if \( f(c) = 0 \), then c is a zero of the polynomial \( f(x) \). These zeros are also known as roots of the polynomial. To identify a zero:
- Substitute the candidate value into the polynomial.
- Simplify the expression.
- Check if the result is zero.
substitution method
The substitution method is a straightforward technique used to find the zeros of a polynomial. It involves substituting a candidate value into the polynomial and solving. If the result is zero, then the candidate is a zero of the polynomial. Here's how to use the substitution method step-by-step:
- Write down the polynomial.
- Select a candidate value to test.
- Substitute this value into the polynomial in place of the variable x.
- Simplify the expression completely.
- Check the result. If it equals zero, the candidate is a zero. If not, it isn't.