/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 107 Verify by substitution that the ... [FREE SOLUTION] | 91Ó°ÊÓ

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Verify by substitution that the given values of \(x\) are solutions to the given equation. \(x^{2}+25=0\) a. \(x=5 i\) b. \(x=-5 i\)

Short Answer

Expert verified
Both \(x = 5i\) and \(x = -5i\) are solutions.

Step by step solution

01

Substitute value for part (a)

Substitute the given value of part (a) into the equation. The given value is \(x = 5i\). So, substitute \(x = 5i\) into the equation \(x^2 + 25 = 0\).
02

Calculate for part (a)

Solve the substituted equation. For \(x = 5i\), we get: \[(5i)^2 + 25 = 0\] Calculate \((5i)^2\): \[25i^2 + 25 = 0\] Since \(i^2 = -1\), \[25(-1) + 25 = 0\] Simplify: \[-25 + 25 = 0\] Which is true. Thus, \(x = 5i\) is a solution.
03

Substitute value for part (b)

Substitute the given value of part (b) into the equation. The given value is \(x = -5i\). So, substitute \(x = -5i\) into the equation \(x^2 + 25 = 0\).
04

Calculate for part (b)

Solve the substituted equation. For \(x = -5i\), we get: \[(-5i)^2 + 25 = 0\] Calculate \((-5i)^2\): \[25i^2 + 25 = 0\] Since \(i^2 = -1\), \[25(-1) + 25 = 0\] Simplify: \[-25 + 25 = 0\] Which is true. Thus, \(x = -5i\) is a solution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Verification by Substitution
Verification by substitution is a method to check if a given value is a solution to an equation. This means substituting a proposed value into the equation to see if the equation holds true.

For example, let's verify if value ‘a = 5i’ is indeed a solution to the equation: \(x^2 + 25 = 0\).

First, substitute \(x\) with \(5i\) into the equation: \((5i)^2 + 25 = 0\).

Next, calculate \((5i)^2\); which is \(25i^2\), and since \(i^2 = -1\), we get \(25(-1)\).

Now, it becomes \(-25 + 25 = 0\), which simplifies to \(0 = 0\), a true statement!

Thus, \(x = 5i\) is indeed a solution.

Repeat the same process with \(x = -5i\). By following this method, you'll understand why the given value works as the solution.
Imaginary Unit
The imaginary unit, represented by \(i\), is a fundamental concept in complex numbers. It is defined as \(i^2 = -1\).

This implies that \(i\) is the square root of -1. Imaginary numbers are numbers that involve this unit \(i\). When squared, \(i\) yields -1, allowing us to manage calculations involving negative square roots.

For instance, in the previous exercise, when squaring \(5i\), we get \((5i)^2\), which simplifies to \(25i^2\).

By knowing that \(i^2 = -1\), we convert it to \(25(-1)\), simplifying the problem.

Imaginary numbers are paired with real numbers to form complex numbers in the format \(a + bi\), where \(a\) and \(b\) are real numbers.
Solving Quadratic Equations
Solving quadratic equations involves finding values of \(x\) that satisfy the equation of the form \(ax^2 + bx + c = 0\).

When dealing with complex or imaginary numbers, the equation might need manipulation using the imaginary unit \(i\).

In the given exercise, we have the quadratic equation \(x^2 + 25 = 0\). This can be rewritten to find values of \(x\) such that \(x^2 = -25\).

By extracting the square roots of both sides, we get \(x = \pm \sqrt{-25}\).

Since \(\sqrt{-1} = i\), this reshapes to \(x = \pm 5i\).

Quadratic equations can often lead to complex solutions, especially when the determinant (\(b^2 - 4ac\)) is negative, involving \(i\). Techniques like factoring, using the quadratic formula, or completing the square are essential tools to find these solutions.

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