/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 74 Simplify each expression. Assume... [FREE SOLUTION] | 91Ó°ÊÓ

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Simplify each expression. Assume that all variable expressions represent positive real numbers. \(\sqrt[4]{243 m^{19} n^{10}}\)

Short Answer

Expert verified
The simplified expression is \(3^{5/4} m^{19/4} n^{5/2}\).

Step by step solution

01

Express the constant in terms of its prime factors

Write 243 as a power of 3. Since 243 is equal to 3 raised to the power of 5, we can rewrite it as \(243 = 3^5\). Our expression thus becomes \(\sqrt[4]{3^5 m^{19} n^{10}}\).
02

Apply the fourth root to each term inside the radical

The fourth root of a product can be distributed to each factor separately. We can rewrite the expression as \(\sqrt[4]{3^5} \cdot \sqrt[4]{m^{19}} \cdot \sqrt[4]{n^{10}}\).
03

Simplify each fourth root

Simplify each term by expressing the exponents as fractions. \(\sqrt[4]{3^5} = 3^{5/4}\), \(\sqrt[4]{m^{19}} = m^{19/4}\), and \(\sqrt[4]{n^{10}} = n^{10/4} = n^{5/2}\).
04

Write the final simplified expression

Combine all the simplified terms to get the final answer: \(3^{5/4} m^{19/4} n^{5/2}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fourth Roots
To start, let's understand what a fourth root is. The fourth root of a number is a value that, when multiplied by itself four times, gives the original number. For example, the fourth root of 16 is 2 because \((2 \cdot 2 \cdot 2 \cdot 2 = 16)\). In mathematical notation, the fourth root of a number x is written as \[ \sqrt[4]{x} \].
Fourth roots involve more complex calculations than square or cube roots, but the idea is the same. Splitting the problem into smaller parts often helps. For instance, if you have \[ \sqrt[4]{a \cdot b} \], you can split it into \(((\sqrt[4]{a}) \cdot (\sqrt[4]{b}))\). This property significantly simplifies calculations.
Exponent Rules
Exponent rules are essential for simplifying expressions. These rules help manage and combine powers of numbers and variables. Here are some key rules:
  • Product Rule: \[ a^m \cdot a^n = a^{m+n} \]
  • Quotient Rule: \[ \frac{a^m}{a^n} = a^{m-n} \]
  • Power Rule: \[ (a^m)^n = a^{m \cdot n} \]
  • Root Rule: \[ \sqrt[n]{a^m} = a^{m/n} \]
In our problem, the root rule is particularly useful. For example, \[ \sqrt[4]{3^5} \] can be simplified using the root rule \((3^{5/4})\). The same applies to variables: \[ \sqrt[4]{m^{19}} = m^{19/4} \] and \[ \sqrt[4]{n^{10}} = n^{5/2} \]. These simplifications help us express complex roots in a manageable form.
Prime Factorization
Prime factorization breaks down a number into its basic prime factors. A prime number is a number greater than 1 that has no positive divisors other than 1 and itself. For example, 243 can be broken down as follows:
243 is divisible by 3, so \[ \frac{243}{3} = 81 \].
81 is also divisible by 3, so \[ \frac{81}{3} = 27 \].
27 can be divided by 3, so \[ \frac{27}{3} = 9 \].
9 can be further divided by 3, so \[ \frac{9}{3} = 3 \].
Finally, 3 is a prime number. Putting it all together, we have \[ 243 = 3 \cdot 3 \cdot 3 \cdot 3 \cdot 3 = 3^5 \].
Understanding prime factorization is crucial for simplifying radical expressions. It allows us to express numbers like 243 in a format that makes it easier to apply rules of exponents and roots. For instance, we rewrite \[ \sqrt[4]{243} \] as \[ \sqrt[4]{3^5} \], simplifying the calculation to \[ 3^{5/4} \].

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