Chapter 0: Problem 33
Determine whether the statement is true or false. a. \(\\{-2,-4,-6\\}\subset\\{-6,-4,-2,0\\}\) b. \(\\{-6,-4,-2,0\\}\subset\\{-2,-4,-6\\}\)
Short Answer
Expert verified
a. True b. False
Step by step solution
01
- Understanding Subsets
A set A is considered a subset of set B if every element of set A is also an element of set B. This is denoted as \(A \subset B\).
02
- Analyzing Part (a)
Check if each element of the set \(\{-2, -4, -6\}\) is also a member of the set \(\{-6, -4, -2, 0\}\).
03
- Verification for Part (a)
Elements of \(\{-2\}\), \(\{-4\}\), and \(\{-6\}\) are indeed in the set \(\{-6, -4, -2, 0\}\). Thus, \(\{-2, -4, -6\}\) is a subset of \(\{-6, -4, -2, 0\}\).
04
- Conclusion for Part (a)
Based on the verification, the statement for part (a) is true.
05
- Analyzing Part (b)
Check if each element of the set \(\{-6, -4, -2, 0\}\) is also a member of the set \(\{-2, -4, -6\}\).
06
- Verification for Part (b)
The element \(0\) in the set \(\{-6, -4, -2, 0\}\) is not in the set \(\{-2, -4, -6\}\). Hence, \(\{-6, -4, -2, 0\}\) is not a subset of \(\{-2, -4, -6\}\).
07
- Conclusion for Part (b)
Based on the verification, the statement for part (b) is false.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Subset Definition
In Set Theory, a subset is a set where every element is also contained in another set. We use the symbol \(\subset\) to denote that set A is a subset of set B, written as \(A \subset B\). For instance, if we have two sets, A = \(\{-2, -4, -6\}\) and B = \(\{-6, -4, -2, 0\}\), to determine if A is a subset of B, we need to check that every element in A is also in B.
If every element in A is found within B, then A is indeed a subset of B. Conversely, if even a single element in A is not in B, then A is not a subset of B. Understanding this concept is crucial to interpreting and working with sets in mathematics.
If every element in A is found within B, then A is indeed a subset of B. Conversely, if even a single element in A is not in B, then A is not a subset of B. Understanding this concept is crucial to interpreting and working with sets in mathematics.
Set Membership
Set membership refers to the relationship between an element and a set. If an element a belongs to set A, we write \(a \in A\). Conversely, if an element a does not belong to set A, we write \(a otin A\).
For example, let's use the sets from the exercise: A = \(\{-2, -4, -6\}\) and B = \(\{-6, -4, -2, 0\}\). Here, \(-2 \in A\), \(-4 \in A\), and \(-6 \in A\). Also, since \(A \subset B\), it means every element of A is also in B, hence \(-2 \in B\), \(-4 \in B\), and \(-6 \in B\).
By verifying the membership of each element, we can determine subset relationships accurately.
For example, let's use the sets from the exercise: A = \(\{-2, -4, -6\}\) and B = \(\{-6, -4, -2, 0\}\). Here, \(-2 \in A\), \(-4 \in A\), and \(-6 \in A\). Also, since \(A \subset B\), it means every element of A is also in B, hence \(-2 \in B\), \(-4 \in B\), and \(-6 \in B\).
By verifying the membership of each element, we can determine subset relationships accurately.
Verification of Subsets
To verify whether one set is a subset of another, we follow a series of steps:
Looking at part (a) of the exercise: we checked that all elements of A = \(\{-2, -4, -6\}\) are in B = \(\{-6, -4, -2, 0\}\). Since this is true for all elements (i.e., \(-2 \in B\), \(-4 \in B\), \(-6 \in B\)), A is a subset of B.
Now for part (b): we verified if all elements of B = \(\{-6, -4, -2, 0\}\) are also in A = \(\{-2, -4, -6\}\). Here, \(0 otin A\), so B is not a subset of A. This verification process helps in making precise determinations about subset relationships.
- Identify elements of set A.
- Check if each element of A is also an element of set B.
- If every element of A is in B, then A is a subset of B, otherwise, it is not.
Looking at part (a) of the exercise: we checked that all elements of A = \(\{-2, -4, -6\}\) are in B = \(\{-6, -4, -2, 0\}\). Since this is true for all elements (i.e., \(-2 \in B\), \(-4 \in B\), \(-6 \in B\)), A is a subset of B.
Now for part (b): we verified if all elements of B = \(\{-6, -4, -2, 0\}\) are also in A = \(\{-2, -4, -6\}\). Here, \(0 otin A\), so B is not a subset of A. This verification process helps in making precise determinations about subset relationships.