Chapter 0: Problem 29
Simplify each expression. a. \(27^{1 / 3}\) b. \((-27)^{1 / 3}\) c. \(-27^{1 / 3}\)
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Chapter 0: Problem 29
Simplify each expression. a. \(27^{1 / 3}\) b. \((-27)^{1 / 3}\) c. \(-27^{1 / 3}\)
These are the key concepts you need to understand to accurately answer the question.
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Cone-shaped paper cups are used at the water cooler in many exercise facilities. Using the formula for the volume of a cone, the volume in cubic centimeters \((\mathrm{cc})\) of this cup is \(V=\frac{\pi(3.8)^{2} \cdot 8}{3}\). Approximate the volume to the nearest cubic centimeter.
The lateral surface area \(A\) of a right circular cone is given by \(A=\pi r \sqrt{r^{2}+h^{2}}\) where \(r\) and \(h\) are the radius and height of the cone. Determine the exact value (in terms of \(\pi\) ) of the lateral surface area of a cone with radius \(6 \mathrm{~m}\) and height \(4 \mathrm{~m}\). Then give a decimal approximation to the nearest meter.
An _____ number is a real number that cannot be expressed as a ratio of two integers.
An inflated balloon has a volume of \(6.0 \mathrm{~L}\) (liters) at sea level, where the pressure is \(1.0 \mathrm{~atm}\) (atmosphere). The balloon is allowed to ascend until the pressure is 0.5 atm. During the ascent, the temperature of the gas in the balloon falls from \(20^{\circ} \mathrm{C}\) to \(-23^{\circ} \mathrm{C}\). Using the ideal-gas equation from chemistry, the new volume (in liters) of the gas in the balloon is \(V=6.0\left(\frac{1.0}{0.5}\right)\left(\frac{250}{293}\right)\). Approximate this volume to the nearest tenth of a liter.
The conjugate of \(3-\sqrt{x}\) is _____.
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