/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 110 Explain the similarity in simpli... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Explain the similarity in simplifying the given expressions. a. \((x+3)(x-3)\) b. \((\sqrt{x}+\sqrt{3})(\sqrt{x}-\sqrt{3})\)

Short Answer

Expert verified
Both expressions simplify using the difference of squares formula to \(x^2 - 9\) and \(x - 3\), respectively.

Step by step solution

01

- Recognize the Pattern

Both expressions are in the form \( (a + b)(a - b) \), known as the difference of squares formula.
02

- Write the Difference of Squares Formula

The formula for the difference of squares states \[ (a + b)(a - b) = a^2 - b^2 \].
03

- Identify a and b for Expression (a)

For the expression \( (x+3)(x-3) \), identify \( a = x \) and \( b = 3 \).
04

- Apply the Formula to Expression (a)

Using the difference of squares formula: \[ (x+3)(x-3) = x^2 - 3^2 = x^2 - 9 \].
05

- Identify a and b for Expression (b)

For the expression \( (\sqrt{x} + \sqrt{3})(\sqrt{x} - \sqrt{3}) \), identify \( a = \sqrt{x} \) and \( b = \sqrt{3} \).
06

- Apply the Formula to Expression (b)

Using the difference of squares formula: \[ (\sqrt{x} + \sqrt{3})(\sqrt{x} - \sqrt{3}) = (\sqrt{x})^2 - (\sqrt{3})^2 = x - 3 \].

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factoring Techniques
Factoring is a method used in algebra to simplify expressions and solve equations. One key factoring technique is the difference of squares. This technique applies when you have a binomial in the form of \((a + b)(a - b)\). Recognizing this pattern allows you to simplify the expression. For example, in the expression \((x+3)(x-3)\), you can see it fits the \((a + b)(a - b)\) form, where \(a = x\) and \(b = 3\). Applying the difference of squares formula, you get \(x^2 - 9\). This same technique can be used in more complex expressions involving square roots, such as \((\text{sqrt}(x)+\text{sqrt}(3))(\text{sqrt}(x)-\text{sqrt}(3))\), where \(a = \text{sqrt}(x)\) and \(b = \text{sqrt}(3)\).
Simplifying Algebraic Expressions
Simplifying algebraic expressions involves making them more manageable or easier to manipulate. To do this, you use various strategies, such as combining like terms or using factoring techniques. By recognizing that expressions like \((x+3)(x-3)\) and \((\text{sqrt}(x) + \text{sqrt}(3))(\text{sqrt}(x) - \text{sqrt}(3))\) fit the difference of squares pattern, they can be simplified quickly.
  • The expression \((x+3)(x-3)\) becomes \(x^2 - 9\).
  • The expression \((\text{sqrt}(x) + \text{sqrt}(3))(\text{sqrt}(x) - \text{sqrt}(3))\) simplifies to \(x - 3\).
By simplifying such expressions, you make solving equations or further manipulation more straightforward.
Pattern Recognition in Algebra
Pattern recognition in algebra is crucial for simplifying complex expressions and solving equations effectively. When you learn to recognize different algebraic patterns, such as the difference of squares, it becomes easier to know which techniques to apply. The difference of squares pattern, identified by expressions like \((a + b)(a - b)\), is a common and useful pattern. Without recognizing this pattern, simplifying expressions like \((x+3)(x-3)\) or \((\text{sqrt}(x) + \text{sqrt}(3))(\text{sqrt}(x) - \text{sqrt}(3))\) can seem daunting. Always look for familiar patterns and apply the appropriate formulas to streamline your work and avoid errors.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The conjugate of \(3-\sqrt{x}\) is _____.

Joelle has a personal web page with 60 gigabytes of memory (approximately \(6 \times 10^{10}\) bytes). She stores math videos on the site for her students to watch outside of class. If each video requires an average of 5 megabytes of memory (approximately \(5 \times 10^{6}\) bytes), how many videos can she store on her website?

The expression \(a^{m / n}\) can be written in radical notation as _________ provided that \(\sqrt[n]{a}\) is a real number.

Suppose that \(x\) represents the smaller of two consecutive integers. a. Write a polynomial that represents the larger integer. b. Write a polynomial that represents the sum of the two integers. Then simplify. c. Write a polynomial that represents the product of the two integers. Then simplify. d. Write a polynomial that represents the sum of the squares of the two integers. Then simplify.

The mean surface temperature \(T_{p}\) (in \({ }^{\circ} \mathrm{C}\) ) of an Earth-like planet can be approximated based on its distance from its primary star \(d\) (in \(\mathrm{km}\) ), the radius of the star \(r\) (in \(\mathrm{km}\) ), and the temperature of the star \(T_{s}\) (in \({ }^{\circ} \mathrm{C}\) ) by the following formula. \(T_{p}=0.7\left(T_{s}+273\right)\left(\frac{r}{d}\right)^{1 / 2}-273\) Use the model to find \(T_{p}\) Suppose the Sun has a mean surface temperature of \(5700^{\circ} \mathrm{C}\) and a radius of approximately \(7.0 \times 10^{5} \mathrm{~km}\). If the Earth is a distance of \(1.49 \times 10^{8} \mathrm{~km}\) from the Sun, approximate the mean surface temperature for the Earth.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.