/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 Sketch the graph of the function... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Sketch the graph of the function. Choose a scale that allows all relative extrema and points of inflection to be identified on the graph. \(y=-x^{3}+3 x^{2}+9 x-2\)

Short Answer

Expert verified
The graph of the function \(y=-x^{3}+3 x^{2}+9 x-2\) is a curve that shows all relative extrema and inflection points. We identify these using the first derivative \(y'= -3x^{2} + 6x + 9\) and second derivative \(y''= -6x + 6\).

Step by step solution

01

First Derivative and Critical Points

Differentiate the function \(y=-x^{3}+3 x^{2}+9 x-2\) to find the first derivative, \(y'= -3x^{2} + 6x + 9\). The critical points can be found by setting the derivative equal to zero and solve for \(x\). The solutions are the x-coordinates of the potential maxima and minima.
02

Second Derivative and Inflection Points

Differentiate the first derivative to get the second derivative: using \(y' = -3x^{2} + 6x + 9\), we find \(y''= -6x + 6\). Points of inflection are given by the solutions of \(y'' = 0\), thus, we need to solve \(-6x + 6 = 0\).
03

Draw the Function Graph

Using the critical points and the points of inflection noted, take additional points to help in plotting the function to get a complete picture. Start by identifying the x and y-intercepts. Then plot the graph, making sure to show all extrema and inflection points.

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