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Optimal Profit The costs to a store for two models of Global Positioning System (GPS) receivers are $$\$ 80$$ and $$\$ 100$$. The $$\$ 80$$ model yields a profit of $$\$ 25$$ and the $$\$ 100$$ model yields a profit of $$\$ 30 .$$ Market tests and available resources indicate the following constraints. \- The merchant estimates that the total monthly demand will not exceed 200 units. \- The merchant does not want to invest more than $$\$ 18,000$$ in GPS receiver inventory. What is the optimal inventory level for each model? What is the optimal profit?

Short Answer

Expert verified
The optimal numbers of the $80 and $100 models and the corresponding optimal profit would be determined using a method for solving linear programming problems under the given set of constraints.

Step by step solution

01

Defining the Variables

Let \(X\) represent the number of units of the $80 model and \(Y\) the number of units of the $100 model. Now the objective is to maximize profit.
02

Constructing the Objective Function

The profit from each $80 model is $25 and from each $100 is $30. Therefore, the total profit \(P\) can be represented as: \(P = 25X + 30Y\) which is what we aim to maximize.
03

Constructing the Constraints

The constraints from the problem are: 1. The total monthly demand will not exceed 200 units: \(X + Y \leq 200\).2. The store does not want to invest more than $18,000: \(80X + 100Y \leq 18000\).3. As the number of units cannot be negative: \(X \geq 0\) and \(Y \geq 0\).
04

Solving the Linear Programming Problem

Using a method suitable for solving linear programming problems such as graphical method or Simplex method, determine the values of \(X\) and \(Y\) that optimize the objective function under the given constraints.
05

Determine the Optimal Profit

Once the values of \(X\) and \(Y\) that optimize the profit are found, these can be substituted back into the profit function to find the optimal profit.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Objective Function
In linear programming, the objective function is what you are trying to maximize or minimize. It's a mathematical representation of the goal you're aiming to achieve. In this particular exercise, the objective function represents the total profit from selling two types of GPS receivers.

To set it up, you need to consider the profit each unit generates. Here, the \(80 model provides a profit of \)25, and the \(100 model offers \)30. Hence, if you let \(X\) be the number of \(80 models and \(Y\) be the number of \)100 models, the objective function can be written as:

\[P = 25X + 30Y\]

The job is to find the values of \(X\) and \(Y\) that yield the maximum possible profit \(P\). This formula is what guides the entire optimization process, clearly showing what needs to be achieved.
Constraints
When working with linear programming, constraints are the limitations or restrictions that must be considered during the optimization process. They define the feasible region where solutions are possible.

In this exercise, three main constraints play a role.
  • The total number of GPS receivers demanded in a month, \(X + Y \), can't be more than 200 units.
  • The total investment in GPS inventory, given by \(80X + 100Y\), should not exceed $18,000.
  • The number of units of each type can't be negative, so \(X \geq 0\) and \(Y \geq 0\).
These constraints need to shape the strategy for finding the optimal number of each model to stock.
Profit Maximization
Profit maximization is a key goal for businesses looking to improve their bottom line. In this context, it involves adjusting the number of each GPS model to maximize total profit.

Consider how different combinations of the models could affect profit, given the constraints. By analyzing how changes in \(X\) and \(Y\) affect the profit function \(P = 25X + 30Y\), and ensuring these stay within the specified limits, you can determine the optimal mix of models for sale that brings in the highest profit.

This process of finding the best solution is the essence of profit maximization in linear programming.
Optimization Problem
An optimization problem in the realm of linear programming is about finding the most effective way to achieve a specific outcome within set constraints. Essentially, it seeks the best possible solution from a pool of feasible options.

In our GPS receiver example, solving the optimization problem involves analyzing the objective function (profit maximization) subject to given constraints on total demand and inventory investment.

Methods like the graphical approach or Simplex method are applied to pinpoint the values of \(X\) and \(Y\) that achieve this.

Understanding and applying these methods helps one efficiently arrive at an optimal decision, perfectly aligning with the needs and limits of the business situation.

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Most popular questions from this chapter

Shoe Sales You are the manager of a shoe store. On Sunday morning you are going over the receipts for the previous week's sales. A total of 320 pairs of cross-training shoes were sold. One style sold for $$\$ 56.95$$ and the other sold for $$\$ 72.95 .$$ The total receipts were $$\$ 21,024$$. The cash register that was supposed to keep track of the number of each type of shoe sold malfunctioned. Can you recover the information? If so, how many of each type were sold?

Optimal Profit A manufacturer produces two models of bicycles. The times (in hours) required for assembling, painting, and packaging each model are shown in the table. $$ \begin{array}{|l|c|c|} \hline \text { Process } & \text { Model A } & \text { Model B } \\ \hline \text { Assembling } & 2 & 2.5 \\ \hline \text { Painting } & 4 & 1 \\ \hline \text { Packaging } & 1 & 0.75 \\ \hline \end{array} $$ The total times available for assembling, painting, and packaging are 4000 hours, 4800 hours, and 1500 hours, respectively. The profits per unit are \(\$ 50\) for model \(\mathrm{A}\) and \(\$ 75\) for model \(\mathrm{B}\). What is the optimal production level for each model? What is the optimal profit?

Reasoning When solving a linear programming problem, you find that the objective function has a maximum value at more than one vertex. Can you assume that there are an infinite number of points that will produce the maximum value? Explain your reasoning.

Investment Portfolio A total of \(\$ 25,000\) is invested in two corporate bonds that pay \(9.5 \%\) and \(14 \%\) simple interest. The total annual interest is \(\$ 3050 .\) How much is invested in each bond?

Maximize the objective function subject to the constraints \(3 x+y \leq 15,4 x+3 y \leq 30\) \(x \geq 0\), and \(y \geq 0\) $$z=2 x+y$$

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