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Solve the system of equations. $$\left\\{\begin{array}{l}2 x+3 y=0 \\ 4 x+3 y-z=0 \\ 8 x+3 y+3 z=0\end{array}\right.$$

Short Answer

Expert verified
The solution to the system of equations is \(x = 0\), \(y = 0\), and \(z = 0\).

Step by step solution

01

Simplifying the equation

Since the coefficients of \(y\) in all equations are the same and \(x\) in second and third equation is a multiple of \(x\) in the first equation, lets subtract first equation from the second and the third equation.The resulting equations are: \[4x - 2x + 3y - 3y - z = 0 \rightarrow 2x - z = 0 \] \[8x - 2x + 3y - 3y + 3z = 0 \rightarrow 6x + 3z = 0\]
02

Rewriting in terms of variables

Rearranging the above equations to represent \(z\) and \(x\) we have: \[z = 2x\]\[6x + 3*(2x) = 0\]
03

Solving for x

Substituting \(z = 2x\) in the equation \(6x + 3*(2x) = 0\), we get \(6x + 6x = 0\), which simplifies to \(12x = 0\). Solving for \(x\), we have \(x = 0\).
04

Solving for z and y

Substitute \(x = 0\) into the equations of \(z\), we get \(z = 0\). Substituting \(x = 0\) into the original equation \(2x + 3y =0\), we get \(y = 0\) as well.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Algebra
Linear Algebra is a branch of mathematics that deals with vectors, vector spaces, and linear equations. It is an essential tool in various fields, including science and engineering. When you hear about Linear Algebra, think about equations that involve unknowns which are brought together through operations like addition and multiplication.

This subject is powerful because it allows you to solve systems of equations using matrices and vectors. For example, a system of equations can often be represented in matrix form, making it easier to handle multiple equations at once. The equations are usually referred to as linear because they represent straight lines when plotted on a graph.

Manipulating these equations using techniques from Linear Algebra offers efficient paths to solving problems that might be too complex for traditional methods. Whether you’re dealing with two equations or ten, Linear Algebra provides the structure to approach the problem systematically.
Simultaneous Equations
Simultaneous equations are a set of equations that you solve at the same time. They contain more than one unknown variable, making the task a bit challenging but feasible with the right approach.

In the exercise, we are dealing with three equations that involve the variables \(x\), \(y\), and \(z\):
  • \(2x + 3y = 0\)
  • \(4x + 3y - z = 0\)
  • \(8x + 3y + 3z = 0\)
Solving simultaneous equations usually involves methods such as substitution or elimination. Here, we simplified by subtracting to eliminate one variable at a time. By aligning the equations side by side, we made strategic choices to cancel out specific variables which led us directly toward finding a solution.

This system revealed that all variables \(x\), \(y\), and \(z\) equate to zero. Thus, solving simultaneous equations aims to find a consistent set of values for each unknown that satisfies all given equations.
Problem Solving Steps
Following a structured approach is crucial in problem solving for systems of equations:**Step 1: Simplify the Equations**
Start by looking at what you can simplify. If equations share similar terms (like the coefficients), you can subtract or add them directly. In our exercise, subtracting the first equation from the others helped reduce complexity.**Step 2: Rewriting in Terms of Variables**
This step involves rearranging what’s left after simplification. Gather like terms together. Sometimes it helps to express one variable in terms of another, as we did by expressing \(z\) in terms of \(x\).**Step 3: Solve for One Variable**
Pick an equation where one variable stands out. Solve it completely to find the value. In our solution, we determined that \(x = 0\).**Step 4: Substitute Back to Solve for Others**
Use the first found value to determine others. Substitute \(x = 0\) back into other simplified equations to find \(z\) and \(y\). This step confirmed that \(z = 0\) and \(y = 0\).By following these steps carefully, not only do you reach the solution efficiently, but you also develop a clear understanding of the problem along the way.

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