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Use a calculator to evaluate the expression. Round your result to three decimal places.\(6^{-\sqrt{2}}\)

Short Answer

Expert verified
The result of the expression, rounded to three decimal places, will depend on the calculator used. However, it should approximately equal 0.252.

Step by step solution

01

Calculate the Square Root

The first operation to perform in the given expression is to calculate the square root of 2. Scientific calculators typically have a square root function denoted by '\(\sqrt{}\)'. Use this function to find the square root of 2.
02

Apply the Exponent

Next, use the result of Step 1 as the exponent of 6. On your calculator, you can usually do this by entering '6', then hitting the '^' button, then entering your result from Step 1. This will give you \(6^{-\sqrt{2}}\).
03

Round to Three Decimal Places

The final step is to round the result from Step 2 to three decimal places. Make sure to only round your final result instead of rounding intermediate steps, which could introduce rounding errors.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Square Root
The square root is a fundamental mathematical operation that determines which number, when multiplied by itself, equals the original number. For example, the square root of 4 is 2, because 2 times 2 equals 4. Mathematically, this is represented as \(\sqrt{4} = 2\).

In practice, calculating a square root can often be done with a scientific calculator. Most calculators feature a square root button, usually represented by the symbol \(\sqrt{}\). By entering the number you wish to find the square root of and pressing this button, you can quickly determine the square root value.

For this exercise, you need to calculate the square root of 2. When you press the square root button after entering the number 2 on your calculator, you will get approximately 1.414. This value is critical as it is used in the next step of applying an exponent.
Scientific Notation
Scientific notation is a way of expressing very large or very small numbers in a compact form. It is particularly useful in science and engineering. Numbers are written in the form of \(a \times 10^b\), where \(a\) is a number greater than or equal to 1 and less than 10, and \(b\) is an integer.

Understanding how to use scientific notation on a calculator can come in handy when dealing with large exponents, such as in the expression \(6^{-\sqrt{2}}\). After computing operations like powers, results can be very large or very small. Rather than writing out numerous zeroes, scientific notation offers a simpler representation.

For instance, the number 0.000123 can be written as \(1.23 \times 10^{-4}\). This expression is easier to read and work with, especially in calculations.
Rounding Decimals
Rounding decimals is the process of reducing the number of significant digits in a number while keeping the representation as accurate as possible. This is crucial in many mathematical and scientific calculations where complete precision is unnecessary or difficult to maintain.

To round a number to a specific decimal place, you look at the digit following the place you are rounding to:
  • If the next digit is 5 or greater, you round up.
  • If it is less than 5, you round down.
For example, if you want to round 3.146 to two decimal places, you look at the third decimal, which is 6, and round up the second decimal to get 3.15.

In the context of the given expression, after computing \(6^{-\sqrt{2}}\), you will obtain a numerical result which might have many digits. You need to round this result to three decimal places as per the requirement of the problem, ensuring clarity and precision in your answer.

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Most popular questions from this chapter

Solve the exponential equation algebraically. Approximate the result to three decimal places.\(\left(1+\frac{0.065}{365}\right)^{365 t}=4\)

Find the constants \(C\) and \(k\) such that the exponential function \(y=C e^{k t}\) passes through the points on the graph.Learning Curve The management at a factory has found that the maximum number of units a worker can produce in a day is 40 . The learning curve for the number of units \(N\) produced per day after a new employee has worked \(t\) days is given by \(N=40\left(1-e^{k t}\right)\) After 20 days on the job, a particular worker produced 25 units in 1 day. (a) Find the learning curve for this worker (first find the value of \(k\) ). (b) How many days should pass before this worker is producing 35 units per day?

Use a graphing utility to solve the equation. Approximate the result to three decimal places. Verify your result algebraically.\(500-1500 e^{-x / 2}=0\)

Automobiles are designed with crumple zones that help protect their occupants in crashes. The crumple zones allow the occupants to move short distances when the automobiles come to abrupt stops. The greater the distance moved, the fewer g's the crash victims experience. (One \(\mathrm{g}\) is equal to the acceleration due to gravity. For very short periods of time, humans have withstood as much as 40 g's.) In crash tests with vehicles moving at 90 kilometers per hour, analysts measured the numbers of g's experienced during deceleration by crash dummies that were permitted to move \(x\) meters during impact. The data are shown in the table. $$ \begin{array}{|l|l|l|l|l|l|} \hline x & 0.2 & 0.4 & 0.6 & 0.8 & 1.0 \\ \hline g \text { 's } & 158 & 80 & 53 & 40 & 32 \\ \hline \end{array} $$A model for these data is given by \(y=-3.00+11.88 \ln x+\frac{36.94}{x}\) where \(y\) is the number of g's. (a) Complete the table using the model.$$ \begin{array}{|l|l|l|l|l|l|} \hline x & 0.2 & 0.4 & 0.6 & 0.8 & 1.0 \\ \hline y & & & & & \\ \hline \end{array} $$(b) Use a graphing utility to graph the data points and the model in the same viewing window. How do they compare? (c) Use the model to estimate the least distance traveled during impact for which the passenger does not experience more than \(30 \mathrm{~g}\) 's. (d) Do you think it is practical to lower the number of g's experienced during impact to fewer than 23 ? Explain your reasoning.

Solve the exponential equation algebraically. Approximate the result to three decimal places.\(\left(1+\frac{0.10}{12}\right)^{12 t}=2\)

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