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Evaluate the logarithm. Round your result to three decimal places.\(\log _{5} \frac{1}{3}\)

Short Answer

Expert verified
-0.683

Step by step solution

01

Break down the logarithm into two

Use the property of logarithms that says the logarithm of a fraction is equal to the logarithm of the numerator minus the logarithm of the denominator. In this case, \(\log _{5} (1/3)\) can be rewritten as \(\log _{5} 1 - \log _{5} 3\).
02

Evaluate the logarithms

First, remember that any number to the power of 0 is 1, so \(\log_{5} 1 = 0\). To calculate \(\log _{5} 3\), use a calculator to get an approximation. This will yield \(\log_{5} 3 \approx 0.68260\).
03

Subtract the two logarithm values

Now subtract the value obtained for \(\log _{5} 3\) from 0 to get the result, which is \(-0.68260\).
04

Round to three decimal places

Round the result to three decimal places, yielding a final answer of \(-0.683\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Logarithmic Properties
Understanding logarithmic properties is crucial when evaluating expressions like \(\log_{5} \frac{1}{3}\). One fundamental property is that the logarithm of a quotient is equal to the difference of the logarithms of the numerator and the denominator. This transformative property allows us to break down complex logarithmic expressions into simpler parts.

To put this into context, consider our exercise: the given expression \(\log_{5} \frac{1}{3}\) can be split into \(\log_{5} 1 - \log_{5} 3\). Additionally, logarithmic properties include knowing that \(\log_{b} 1 = 0\) for any base \(b\), because any number raised to the power of 0 is 1. Other properties, such as the logarithm of a product or the power rule, are equally useful but not needed for this exercise. It's by applying these properties that we can simplify and evaluate logarithms step by step.
Fractional Logarithms
Fractional logarithms are those where the argument (the value we're taking the logarithm of) is a fraction. As seen in the exercise, dealing with \(\log_{5} \frac{1}{3}\) presents us with a fractional argument. It's vital to remember that this does not change the fundamental properties of logarithms; rather, it just requires an additional step of breaking down the fraction.

When working with fractional logarithms, the goal is to express the logarithm in terms of easier-to-work-with numbers. In the case of this example, we achieve this by turning the original logarithm of a fraction into a subtraction problem involving two simpler logarithms, one of which is often a known constant like 0 or 1 due to the identity \(\log_{b} 1 = 0\).
Logarithm Subtraction
Logarithm subtraction comes into play after using the property that allows us to break a single logarithm of a quotient into the difference of two logarithms. Once we have two separate logarithms like \(\log_{5} 1\) and \(\log_{5} 3\), subtraction is straightforward.

In our exercise, after determining the values of these two logarithms, we perform the subtraction: 0 (the value of \(\log_{5} 1\)) minus the numerical approximation of \(\log_{5} 3\). The result of this subtraction can be simplified to a single value. In some cases, like this one, the result may be negative, which is perfectly valid. Remember to round your final answer according to the requirement of the problem, ensuring precision and correctness.

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Most popular questions from this chapter

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