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Apply the Inverse Property of logarithmic or exponential functions to simplify the expression.\(\ln e^{2 x-1}\)

Short Answer

Expert verified
The simplified expression of \(\ln e^{2 x-1}\) is \(2x - 1\).

Step by step solution

01

Apply the Inverse Property

The inverse property states \( \ln (e^x) = x \), meaning the logarithm and exponential functions cancel each other out when the base of the exponent and the base of the logarithm are the same. In this problem, we have the expression \( \ln (e^{2x-1}) \). So, we can apply the inverse property to reduce this to \(2x-1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Logarithm Simplification
Understanding the process of logarithm simplification can be empowering when working through algebraic problems. At its core, logarithm simplification involves applying rules that allow us to rewrite logarithmic expressions in a more manageable form, often simplifying computations or paving the way for further algebraic manipulation. If, for example, we encounter an expression like \(\ln e^{2 x-1}\), our goal is to simplify it.

The inverse property of logarithms states that the natural logarithm function, denoted by \(\ln\), is the inverse of the exponential function \(e^x\). Thus, when you have an expression \(\ln(e^y)\), where \(y\) is any algebraic expression, you can simplify it directly to \(y\). This is a powerful tool, as it allows the simplification of expressions that might otherwise appear complex. Our given expression \(\ln e^{2 x-1}\) simplifies to \(2x-1\) following this inverse property, making the problem much more straightforward to handle.
Exponential Functions
The concept of exponential functions is foundational in both algebra and calculus. These functions are defined by the form \(f(x) = a^x\), where \(a\) is a constant base and \(x\) is the exponent. An exponential function is distinctive because the variable \(x\) is the exponent, which leads to rapid growth or decay of the function's value as \(x\) changes. The most important exponential function in mathematics is the natural exponential function, \(e^x\), where \(e\) is Euler's number, approximately equal to 2.71828.

It is essential because it arises naturally in many areas of mathematics, including compound interest, population growth, and the behavior of radioactive materials. Moreover, in calculus, \(e^x\) is notable for being the only function that is its own derivative, which has far-reaching implications in the field of differential equations and mathematical modelling.
Properties of Logarithms
To master properties of logarithms, one must first understand what a logarithm is: a way to solve for the exponent in an exponential equation. There are several key properties of logarithms that you can use to manipulate and simplify logarithmic expressions before applying the inverse property. These properties include:
  • Product Property: \(\log_b(mn) = \log_b(m) + \log_b(n)\), which allows you to transform the logarithm of a product into a sum of logarithms.
  • Quotient Property: \(\log_b(\frac{m}{n}) = \log_b(m) - \log_b(n)\), letting you turn the logarithm of a quotient into a difference.
  • Power Property: \(\log_b(m^n) = n\log_b(m)\), which allows you to bring the exponent in a logarithm down as a coefficient.
Using these properties not only simplifies expressions but can also help when solving more complex equations involving logarithms.
Algebraic Expressions
Dealing with algebraic expressions is at the heart of algebra. These expressions are combinations of numbers, variables, and arithmetic operations. When solving for unknowns within these expressions, it is crucial to understand how to appropriately apply the laws of algebra, which include commutative, associative, and distributive laws, among others.

Familiarity with these concepts enables one to manipulate and simplify expressions effectively. For example, in the expression \(2x-1\) derived from the simplification of logarithmic function earlier, we can apply algebraic operations to solve for \(x\) when equated to a value or to expand upon it if included in larger expressions. Mathematics often involves transforming complex expressions into simpler ones, or vice versa, to solve a problem. The ease and accuracy of solving algebraic problems depend largely on a robust understanding of these fundamental principles.

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Most popular questions from this chapter

The logarithm of the quotient of two numbers is equal to the difference of the logarithms of the numbers.

The number \(V\) of varieties of suburban nondomesticated wildlife in a community is approximated by the model \(V=15 \cdot 10^{0.02 x}, \quad 0 \leq x \leq 36\) where \(x\) is the number of months since the development of the community was completed. Use this model to approximate the number of months since the development was completed when \(V=50\).

Bacteria Growth The number \(N\) of bacteria in a culture is given by the model \(N=100 e^{k t}\), where \(t\) is the time (in hours), with \(t=0\) corresponding to the time when \(N=100\). When \(t=6\), there are 140 bacteria. How long does it take the bacteria population to double in size? To triple in size?

Domestic Demand The domestic demands \(D\) (in thousands of barrels) for refined oil products in the United States from 1995 to 2005 are shown in the table. (Source: U.S. Energy Information Administration)$$ \begin{array}{|c|c|} \hline \text { Year } & \text { Demand } \\ \hline 1995 & 6,469,625 \\ \hline 1996 & 6,701,094 \\ \hline 1997 & 6,796,300 \\ \hline 1998 & 6,904,705 \\ \hline 1999 & 7,124,435 \\ \hline 2000 & 7,210,566 \\ \hline \end{array} $$$$ \begin{array}{|c|c|} \hline \text { Year } & \text { Demand } \\ \hline 2001 & 7,171,885 \\ \hline 2002 & 7,212,765 \\ \hline 2003 & 7,312,410 \\ \hline 2004 & 7,587,546 \\ \hline 2005 & 7,539,440 \\ \hline \end{array} $$(a) Use a spreadsheet software program to create a scatter plot of the data. Let \(t\) represent the year, with \(t=5\) corresponding to 1995 . (b) Use the regression feature of a spreadsheet software program to find an exponential model for the data. Use the Inverse Property \(b=e^{\ln b}\) to rewrite the model as an exponential model in base \(e\). (c) Use the regression feature of a spreadsheet software program to find a logarithmic model \((y=a+b \ln x)\) for the data. (d) Use a spreadsheet software program to graph the exponential model in base \(e\) and the logarithmic model with the scatter plot. (e) Use both models to predict domestic demands in 2008 , 2009, and \(2010 .\) Do both models give reasonable predictions? Explain.

Find the time required for a \(\$ 1000\) investment to double at interest rate \(r\), compounded continuously.\(r=0.0875\)

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