/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 Solve for \(x\).\(\ln (2 x-1)=0\... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve for \(x\).\(\ln (2 x-1)=0\)

Short Answer

Expert verified
The solution for \( x \) is 1

Step by step solution

01

Start with the given equation

The original equation is \( \ln (2x - 1) = 0 \)
02

Use logarithmic property

It is known that \( \ln(a) = 0 \) if and only if \( a=1 \). With this principle, equate the term that the logarithm acts on to 1. That gives the equation \( 2x - 1 = 1 \)
03

Solve for \( x \)

To solve for \( x \), first add 1 to both sides of the equation to balance it. That gives \( 2x = 2 \). Next, divide both sides of the equation by 2 to solve for \( x \) which gives \( x = 1 \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Natural Logarithm Properties
The natural logarithm, denoted as \( \ln(x) \) and alternatively known as the Napierian logarithm, has a base of \( e \)—Euler's number, which is approximately 2.71828. This special logarithm comes with its unique set of properties that are vital for solving logarithmic equations.

One fundamental property used often is that \( \ln(1) = 0 \) since any number raised to the power of 0 is 1, and \( e^0 = 1 \). Another key property is the inverse nature of exponential and logarithmic functions; for \( x > 0 \), \( \ln(e^x) = x \) and \( e^{\ln(x)} = x \). This relationship is essential when unraveling logarithmic equations.

Understanding these properties empowers students to solve logarithmic equations efficiently by recognizing patterns and applying the correct operations to isolate the variable.
Logarithmic Equation Steps
Solving logarithmic equations typically involves a sequence of steps that systematically unfold the solution. Here's a breakdown of those steps, tailored to our example \( \ln(2x - 1) = 0 \):

1. Identify the logarithmic term.
2. Apply logarithmic properties, such as \( \ln(a) = 0 \) implies \( a = 1 \), to rewrite the equation in an equivalent, but simpler, form.
3. Perform algebraic manipulations to solve for the variable. This often includes operations such as addition, subtraction, multiplication, division, and sometimes even using properties of exponents when the equation is more complex.

By following these structured steps, students can simplify the process of solving logarithmic equations and reduce the risk of errors.
Algebraic Manipulation
Algebraic manipulation is a critical skill in mathematics, as it involves rearranging equations and expressions using arithmetic operations and algebraic properties to solve for variables or simplify expressions.

In the context of logarithmic equations, such as our exercise \( \ln(2x - 1) = 0 \), algebraic manipulation comes into play after applying logarithmic properties. Students are expected to:
  • Isolate the terms involving the variable,
  • Combine like terms,
  • Use inverse operations to get the variable on one side of the equation,
  • And finally, simplify to find the solution.
The judicious application of these algebraic techniques is essential not only for finding the correct solution but also for developing a solid understanding of the underlying mathematical principles.

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Most popular questions from this chapter

Aged Population The table shows the projected U.S. populations \(P\) (in thousands) of people who are 85 years old or older for several years from 2010 to \(2050 . \quad\) (Source: U.S. Census Bureau)$$ \begin{array}{|c|c|} \hline \text { Year } & 85 \text { years and older } \\ \hline 2010 & 6123 \\ \hline 2015 & 6822 \\ \hline 2020 & 7269 \\ \hline 2025 & 8011 \\ \hline 2030 & 9603 \\ \hline 2035 & 12,430 \\ \hline 2040 & 15,409 \\ \hline 2045 & 18,498 \\ \hline 2050 & 20,861 \\ \hline \end{array} $$(a) Use a graphing utility to create a scatter plot of the data. Let \(t\) represent the year, with \(t=10\) corresponding to 2010 . (b) Use the regression feature of a graphing utility to find an exponential model for the data. Use the Inverse Property \(b=e^{\ln b}\) to rewrite the model as an exponential model in base \(e\). (c) Use a graphing utility to graph the exponential model in base \(e\). (d) Use the exponential model in base \(e\) to estimate the populations of people who are 85 years old or older in 2022 and in 2042 .

Stocking a Lake with Fish \(\quad\) A lake is stocked with 500 fish, and the fish population \(P\) increases according to the logistic curve \(P=\frac{10,000}{1+19 e^{-t / 5}}, \quad t \geq 0\) where \(t\) is the time (in months).

Find the time required for a \(\$ 1000\) investment to double at interest rate \(r\), compounded continuously.\(r=0.085\)

Solve the exponential equation algebraically. Approximate the result to three decimal places.\(6\left(2^{3 x-1}\right)-7=9\)

Bacteria Growth The number \(N\) of bacteria in a culture is given by the model \(N=250 e^{k t}\), where \(t\) is the time (in hours), with \(t=0\) corresponding to the time when \(N=250\). When \(t=10\), there are 320 bacteria. How long does it take the bacteria population to double in size? To triple in size?

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