/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 Decide whether the integral is i... [FREE SOLUTION] | 91Ó°ÊÓ

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Decide whether the integral is improper. Explain your reasoning. $$ \int_{1}^{\infty} x^{2} d x $$

Short Answer

Expert verified
The integral \(\int_{1}^{\infty} x^{2} dx\) is an improper integral since the interval of integration is infinite.

Step by step solution

01

Identify the limits of integration and the function to be integrated

The given integral is \(\int_{1}^{\infty} x^{2} dx\). Here, the limits of integration are 1 and infinity (\infty), and the function to be integrated \(f(x) = x^{2}\).
02

Determine if the integral is improper

An integral is improper if either the interval of integration is infinite, or the function to be integrated approaches infinity at one or more points in the interval of integration. In this case, the interval of integration is from 1 to infinity, which is an infinite interval. Therefore, this is an improper integral.

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Most popular questions from this chapter

Determine whether the improper integral diverges or converges. Evaluate the integral if it converges. $$ \int_{1}^{\infty} \frac{1}{\sqrt[3]{x}} d x $$

Use a spreadsheet to complete the table for the specified values of \(a\) and \(n\) to demonstrate that \(\lim _{x \rightarrow \infty} x^{n} e^{-a x}=0, \quad a>0, n>0\) \begin{tabular}{|l|l|l|l|l|} \hline\(x\) & 1 & 10 & 25 & 50 \\ \hline\(x^{n} e^{-a x}\) & & & & \\ \hline \end{tabular} $$ a=2, n=4 $$

Median Age The table shows the median ages of the U.S. resident population for the years 1997 through \(2005 .\) (Source: U.S. Census Bureau) \begin{tabular}{|l|c|c|c|c|c|} \hline Year & 1997 & 1998 & 1999 & 2000 & 2001 \\ \hline Median age & \(34.7\) & \(34.9\) & \(35.2\) & \(35.3\) & \(35.6\) \\ \hline \end{tabular} \begin{tabular}{|l|c|c|c|c|} \hline Year & 2002 & 2003 & 2004 & 2005 \\ \hline Median age & \(35.7\) & \(35.9\) & \(36.0\) & \(36.2\) \\ \hline \end{tabular} (a) Use Simpson's Rule to estimate the average age over the time period. (b) A model for the data is \(A=31.5+1.21 \sqrt{t}\), \(7 \leq t \leq 15\), where \(A\) is the median age and \(t\) is the year, with \(t=7\) corresponding to 1997 . Use integration to find the average age over the time period. (c) Compare the results of parts (a) and (b).

Use the definite integral below to find the required arc length. If \(f\) has a continuous derivative, then the arc length of \(f\) between the points \((a, f(a))\) and \((b, f(b))\) is \(\int_{b}^{a} \sqrt{1+\left[f^{\prime}(x)\right]^{2}} d x\) Arc Length A fleeing hare leaves its burrow \((0,0)\) and moves due north (up the \(y\) -axis). At the same time, a pursuing lynx leaves from 1 yard east of the burrow \((1,0)\) and always moves toward the fleeing hare (see figure). If the lynx's speed is twice that of the hare's, the equation of the lynx's path is \(y=\frac{1}{3}\left(x^{3 / 2}-3 x^{1 / 2}+2\right)\) Find the distance traveled by the lynx by integrating over the interval \([0,1]\).

Approximate the integral using (a) the Trapezoidal Rule and (b) Simpson's Rule for the indicated value of \(n\). (Round your answers to three significant digits.) $$ \int_{0}^{2} e^{-x^{2}} d x, n=2 $$

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