/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 Determine whether the improper i... [FREE SOLUTION] | 91Ó°ÊÓ

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Determine whether the improper integral diverges or converges. Evaluate the integral if it converges, and check your results with the results obtained by using the integration capabilities of a graphing utility. $$ \int_{0}^{27} \frac{5}{\sqrt[3]{x}} d x $$

Short Answer

Expert verified
The improper integral converges and its value is \(13.5\).

Step by step solution

01

Rewrite the function

First, rewrite the function in a form that allows easier integration. The integrand, \( \frac{5}{\sqrt[3]{x}} \) can be written as \(5x^{-1/3}\).
02

Application of the Power Rule for Integration

Apply the power rule, which states: \[ \int x^{n} dx = \frac{x^{n+1}}{n+1}+C\], where \(n ≠ -1\). For our function, \[ \int_{0}^{27} x^{-1/3}\ dx = \left[ \frac{3}{2}x^{2/3} \right]_0^{27}\]. We get the expression \( \frac{3}{2} \times (27)^{2/3} - \frac{3}{2} \times (0)^{2/3}\).
03

Evaluation of the Definite Integral

Compute the values to get the definite integral. We find that \((27)^{2/3} = 9\) and \((0)^{2/3} = 0\). So, the integral becomes \( \frac{3}{2} \times 9 - \frac{3}{2} \times 0 = 13.5\). Since the integral is a real number, it converges and its value is 13.5.

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Most popular questions from this chapter

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