Chapter 11: Problem 43
Evaluate the definite integral. $$ \int_{0}^{1} e^{2 x} \sqrt{e^{2 x}+1} d x $$
Short Answer
Expert verified
The value of the given definite integral is \(2\sqrt{e^{2}+1} - \frac{2}{3}(e^{2}+1)^{3/2} - 2\sqrt{2} + \frac{4}{3}\).
Step by step solution
01
Choose an appropriate substitution
Inspecting the integrand, there is a clear candidate for substitution: \(u=e^{2x}+1\). This choice will considerably simplify the square root in the integrand, and its differential \(du= 2e^{2x} dx\) will cancel out the \(e^{2x}\) in the integrand as well.
02
Change the boundaries of the integral
Substituting the limits of integration, at \(x=0\), \(u=e^{2*0} +1=2\), and at \(x=1\), \(u=e^{2*1} +1=e^2+1\). This gives new limits of integration \([2, e^2+1]\).
03
Rewrite the integral in terms of u
We can now rewrite our integral in terms of \(u\). Keep in mind that every \(dx\) becomes \(du/2e^{2x}=\frac{du}{2u-1}\). Therefore, the integral becomes, \(\int_{2}^{e^{2}+1} \sqrt{u} \frac{du}{2u-1}\). The \(2u-1\) can be moved out of the fraction that is under the integral, giving us \(\frac{1}{2}\int_{2}^{e^{2}+1} \frac{\sqrt{u}}{u-1} du\).
04
Evaluate the integral
The integrand \(\frac{\sqrt{u}}{u-1}\) can be simplified to \(u^{-1/2} - u^{-3/2}\). Therefore, the antiderivative between 2 and \(e^2+1\) can be calculated. This antiderivative is \(2u^{1/2} - \frac{2}{3} u^{1/2}\). Substituting the upper and lower limits of the integral yields the final result.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Substitution Technique
Substitution is a method that helps simplify complex integrals by changing variables. The goal is to make the integral easier to solve. In our exercise, the expression inside the square root, \(e^{2x}+1\), suggests a straightforward substitution. By letting \(u = e^{2x} + 1\), we transform the integrand.
Here’s how you can use it effectively:
Here’s how you can use it effectively:
- Identify a part of the integrand that complicates the integration. This might include a function inside a square root, logarithm, or exponential function.
- Choose a substitution that simplifies this expression, such as \(u = f(x)\).
- Derive \(du\) in terms of \(dx\), which is needed for changing the differential as well. In our case, \(du = 2e^{2x} dx\).
Integration Bounds
When using substitution, converting the integration bounds is crucial to maintaining the accuracy of the integral.
Upon substituting \(u = e^{2x}+1\), the original variable, \(x\), has limits of 0 and 1. It's necessary to derive new limits in terms of \(u\).
Upon substituting \(u = e^{2x}+1\), the original variable, \(x\), has limits of 0 and 1. It's necessary to derive new limits in terms of \(u\).
- Start with the lower bound: When \(x=0\), substituting gives \(u=2\).
- Next, consider the upper bound: When \(x=1\), substituting gives \(u=e^2+1\).
Antiderivative Calculation
The calculation of the antiderivative is pivotal in obtaining the solution to a definite integral. Once the integral's variable is substituted and the new bounds set, the next step is to find its antiderivative.
In the reformulated integral, \(\int \frac{\sqrt{u}}{u-1} du\), simplifying and finding the antiderivative involves expressing the integrand in a more workable form. Here, it transforms into: \(u^{-1/2} - u^{-3/2}\).
In the reformulated integral, \(\int \frac{\sqrt{u}}{u-1} du\), simplifying and finding the antiderivative involves expressing the integrand in a more workable form. Here, it transforms into: \(u^{-1/2} - u^{-3/2}\).
- Find the antiderivative of each term separately.
- For \(u^{-1/2}\), the antiderivative is \(2u^{1/2}\).
- For \(u^{-3/2}\), it is \(-\frac{2}{3}u^{-1/2}\).