Chapter 11: Problem 23
Find the indefinite integral and check the result by differentiation. $$ \int 5 u \sqrt[3]{1-u^{2}} d u $$
Short Answer
Step by step solution
Define the Components to Use for a Substitution
Rewrite the Integral in Terms of the New Variable
Compute the Integral
Substitute Back to the Original Variable
Checking the Result by Differentiating
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Integration by Substitution
\[ \int 5 u \sqrt[3]{1-u^{2}} d u \]
becomes more approachable when we choose a substitution to simplify the integrand. By setting\(v = 1 - u^{2}\),
we transform the integral into a new variable, making it easier to work with. We calculated\(d v = -2 u d u\),
and therefore\(-1/2 dv = u du\).
Then we substitute both\(u du\)
and\(1-u^{2}\) (\(v\))
in the original integral to rewrite it in terms of \(v\).This technique is invaluable as it transforms complex integrals into simpler forms that are easier to evaluate.Power Rule of Integration
\(x^n\).
To apply the power rule, we increase the exponent by one and divide by the new exponent. For instance, the indefinite integral of\(x^n\)
is\(\frac{x^{n+1}}{n+1} + C\),
where \(C\) is the constant of integration. In the given problem, after applying the integration by substitution, we obtained\[-5/2 \int v^{1/3} d v\],
which requires the power rule for integration. By adding 1 to the exponent and dividing by the new exponent, the integral evaluates to\[-15/8 v^{4/3}\].
The power rule simplifies the process of finding integrals, making it an essential tool for solving integration problems.Differentiation
\[-15/8 (1 - u^{2})^{4/3}\],
we differentiate this expression with respect to \(u\) to verify our solution. The process of differentiation should reverse integration, leading us back to the integrand of\[5 u \sqrt[3]{1-u^{2}}\].
If successful, differentiation not only gives us confidence in our work but also deepens our understanding of how integration and differentiation are interconnected operations.