/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 38 Solve the quadratic equation usi... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve the quadratic equation using any convenient method. $$ x^{2}-2 x+5=x^{2}-5 $$

Short Answer

Expert verified
The solution to the given quadratic equation \( x^{2}-2 x+5=x^{2}-5 \) is \( x = -5 \)

Step by step solution

01

Simplify the Equation

Both sides of the equation have the same degrees. Thus, we will simplify by subtracting \(x^{2}\) from both sides. This will give \( -2x + 5 = -5 \). Then we will need to bring all the terms on one side with the objective of having \( ax^{2} + bx + c = 0 \) form. This will lead to the equation \( -2x + 10 = 0 \).
02

Find the Value of x

After obtaining the simplified equation in the form \( -2x + 10 = 0 \), The next step is to solve for x. It's a simple linear equation at this state. To solve for x, divide the equation by -2 to isolate x. This will give \( x = 10 / -2 = -5 \).
03

Check the Answer

We need to verify if the value obtained in the previous step is correct. This is done by substituting x = -5 into the original equation \( x^{2}-2 x+5=x^{2}-5 \). After substitution, both sides of the equation will be equal, confirming that the solution is correct.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Equation
A quadratic equation is a type of polynomial equation of the second degree, which means it involves at least one term that is squared. The general form of a quadratic equation is \( ax^{2} + bx + c = 0 \), where \( a \), \( b \), and \( c \) are constants, and \( a \) is not zero. The solutions to these equations are known as the roots and can be found using various methods such as factoring, completing the square, using the quadratic formula, or graphing.

The quadratic equation in the exercise simplifies to a linear equation, but it's essential to understand that typically, a quadratic equation may have two real solutions, one real solution, or two complex solutions. These solutions are the x-values where the parabola, the graph of the quadratic function, crosses the x-axis.
Algebraic Equations
An algebraic equation is a mathematical statement that shows the equality of two expressions with one or more unknown variables. Quadratic equations are a subset of algebraic equations, but algebraic equations can also be linear, cubic, quartic, and so on, depending on the highest degree (power) of the variable. Algebraic equations are fundamental in expressing real-world problems and can be used to depict relationships between quantities. When solving these equations, the goal is to isolate the variable to find the value or values that make the equation true.

In the provided exercise, we initially have a quadratic equation that transforms into a simpler algebraic equation, specifically a linear equation after simplifying.
Linear Equations
Linear equations are the simplest type of algebraic equations and involve variables that are to the first power only. The standard form of a linear equation is \( ax + b = 0 \), where \( a \) and \( b \) are constants. These equations graph as straight lines and have a single solution where the line crosses the x-axis.

In the context of the exercise, after simplification, the quadratic equation reduced to a linear equation \( -2x + 10 = 0 \). Solving linear equations is typically more straightforward than solving quadratic equations, as it usually involves basic arithmetic operations to isolate the variable.
Equation Simplification
Equation simplification is a critical process in algebra which involves rewriting an equation to make it easier to solve. Simplifying might include combining like terms, removing parentheses, or canceling common factors. The goal is to consolidate the equation to its simplest form without changing its solutions.

For instance, in the given exercise, equation simplification was crucial. By subtracting \( x^{2} \) from both sides, we eliminated the quadratic term, transforming the equation into a linear form. Simplification often aids in revealing the structure of the equation and can turn a seemingly complex problem into a more manageable one.

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Most popular questions from this chapter

Consider the domains of the expressions \(\sqrt[3]{x^{2}-7 x+12}\) and \(\sqrt{x^{2}-7 x+12}\). Explain why the domain of \(\sqrt[3]{x^{2}-7 x+12}\) consists of all real numbers.

The revenue \(R\) for selling \(x\) units of a product is \(R=25.95 x .\) The cost \(C\) of producing \(x\) units is $$ C=13.95 x+125,000 $$ In order to obtain a profit, the revenue must be greater than the cost. For what values of \(x\) will this product return a profit?

The average price \(G\) (in dollars) of generic prescription drugs from 1998 to 2005 can be modeled by \(G=2.005 t+0.40, \quad 8 \leq t \leq 15\) where \(t\) represents the year, with \(t=8\) corresponding to \(1998 .\) Use the model to find the year in which the price of the average generic drug prescription exceeded \(\$ 19\).

Solve the inequality. Then graph the solution set on the real number line. \(|x-5|<0\)

The revenue \(R\) and cost \(C\) for a product are given by \(R=x(50-0.0002 x)\) and \(C=12 x+150,000\), where \(R\) and \(C\) are measured in dollars and \(x\) represents the number of units sold (see figure). (a) How many units must be sold to obtain a profit of at least \(\$ 1,650,000 ?\) (b) The demand equation for the product is \(p=50-0.0002 x\) where \(p\) is the price per unit. What prices will produce a profit of at least \(\$ 1,650,000 ?\) (c) As the number of units increases, the revenue eventually decreases. After this point, at what number of units is the revenue approximately equal to the cost? How should this affect the company's decision about the level of production?

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