Chapter 8: Problem 86
Exercises 86-88 will help you prepare for the material covered in the next section. $$\text { Evaluate } \frac{n !}{(n-r) !} \text { for } n-20 \text { and } r-3$$.
Short Answer
Expert verified
The evaluation of the given expression \(\frac{n!}{(n-r)!}\) for n=20 and r=3 is 6840.
Step by step solution
01
Understanding Factorial
The factorial of a number 'a', denoted as 'a!', is the product of all positive integers up to 'a'. The factorial function can be defined by the product \(n! = n × (n−1) × (n−2) × ... × 3 × 2 × 1\), and important to note that the factorial of 0 is 1, denoted \(0! = 1\). Therefore, when n is 20 and r is 3, \(n!\) is the product of all positive integers up to 20 and \((n-r)!\) is the product of all positive integers up to 20 - 3 = 17.
02
Evaluating Factorial expression
To simplify the equation \(\frac{n!}{(n-r)!}\) for n=20 and r=3, substitute these values into the equation, which gives: \(\frac{20!}{(20-3)!} = \frac{20!}{17!}\). This simplifies to the product of 20, 19, and 18 because the remaining terms from 17 to 1 in the numerator and the denominator will cancel each other out. Hence, \(\frac{20!}{17!} = 20 × 19 × 18\).
03
Final Evaluation
Finally, calculate the product 20 × 19 × 18 = 6840.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Factorial Notation
Factorial notation is a mathematical expression that helps in counting the number of ways to arrange or order a set of objects. This notation uses an exclamation point, which might remind you of excitement in writing, but in math, it has a different kind of excitement. When we say '5!', we're not shouting the number five; we're saying 5 factorial, which is equal to the product of all positive integers from 5 down to 1. In other words,
\(5! = 5 \times 4 \times 3 \times 2 \times 1\).
The beauty of factorials is that they're straightforward — multiply all whole numbers up until the number you're working with.
\(5! = 5 \times 4 \times 3 \times 2 \times 1\).
The beauty of factorials is that they're straightforward — multiply all whole numbers up until the number you're working with.
- For instance, \(4! = 4 \times 3 \times 2 \times 1 = 24\).
- Similarly, \(6! = 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 720\).
Permutations
Permutations relate to the different ways in which a set of objects can be ordered or arranged. This concept is all about sequences and how many different sequences you can create from a specific number of items. If we have three books and want to know in how many ways we can arrange them on a shelf, we can use permutations to find the answer.
The formula for permutations when you're arranging 'n' objects taken 'r' at a time is expressed as: <\[ P(n, r) = \frac{n!}{(n-r)!} \]>
When the order matters, permutations come into play. Here’s an easy tip to remember: if you can shuffle it and it makes a difference, that's permutations at work. For example, the order of the letters in a password counts, so finding all possible passwords is a job for permutations.
The formula for permutations when you're arranging 'n' objects taken 'r' at a time is expressed as: <\[ P(n, r) = \frac{n!}{(n-r)!} \]>
When the order matters, permutations come into play. Here’s an easy tip to remember: if you can shuffle it and it makes a difference, that's permutations at work. For example, the order of the letters in a password counts, so finding all possible passwords is a job for permutations.
Algebraic Expressions
Algebraic expressions are combinations of constants, variables, and arithmetic operations. Think of them as math's way of transforming real-world problems into a language that computers and calculators understand.
Breaking Down Expressions
An expression can look complex, but it's usually just a combination of simpler parts. For example, \(3x^2 - 2x + 5\) includes:- A variable (x)
- Exponents (\(x^2\))
- Coefficients (3 in front of the \(x^2\), -2 in front of the x)
- A constant term (+5)
Simplifying Factorials
Simplifying factorials may sound daunting, but it's just a matter of breaking down the numbers and canceling out what isn't needed. When we have a fraction with factorials in the numerator and denominator, like \(\frac{n!}{(n-r)!}\), we can often cancel out a large chunk of the equation.
As seen in our example from earlier, when evaluating \(\frac{20!}{17!}\), we were able to cancel out the terms from 17 to 1 in both the numerator and the denominator because they are identical, leaving us with just the product of 20, 19, and 18.
This simplification isn't just a trick; it's a powerful tool.
As seen in our example from earlier, when evaluating \(\frac{20!}{17!}\), we were able to cancel out the terms from 17 to 1 in both the numerator and the denominator because they are identical, leaving us with just the product of 20, 19, and 18.
This simplification isn't just a trick; it's a powerful tool.