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Chapter 8: Problem 59

Explain how to find or probabilities with mutually exclusive events. Give an example.

Short Answer

Expert verified
The probability of 'or' with mutually exclusive events is simply the sum of the probabilities of each event. If Event A and Event B are mutually exclusive, then the probability that either A or B will occur is found using the formula: \(P(A \cup B) = P(A) + P(B)\). For instance, with a six-sided dice, where A is getting a 2, and B is getting a 5, the probability that either event A or event B would occur is \(1/3\).

Step by step solution

01

Definition of Mutually Exclusive Events

Mutually exclusive events are events that cannot happen at the same time. In other words, if one event happens, the other one cannot. For example, throwing a dice and getting either 2 or 5.
02

Definition of 'Or' in Probabilities

The term 'or' in probability refers to the occurrence of at least one of the events. For instance, when we say Event A or Event B, it means either A or B or both can occur.
03

Finding 'Or' Probabilities with Mutually Exclusive Events

For mutually exclusive events A and B, the probability that either event A or event B will occur is given by the formula: \(P(A \cup B) = P(A) + P(B)\). The symbol '\(\cup\)' denotes the union of two sets, which corresponds to the 'or' in probabilities.
04

Example of Mutually Exclusive Events and 'Or' Probabilities

Let's consider an example with a six-sided dice. Let's Event A be getting a 2, and Event B be getting a 5. These events are mutually exclusive as you can't get both on a single toss of the dice. Suppose you roll the dice one time, the probability of each event is \(1/6\). So, applying the formula, we get \(P(A \cup B) = P(A) + P(B) = 1/6 + 1/6 = 2/6 = 1/3\). Thus, the chance that either a 2 or a 5 will be rolled on a single toss of a die is \(1/3\).

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Most popular questions from this chapter

Explain how to distinguish between permutation and combination problems.

Suppose that it is a week in which the cash prize in Florida's LOTTO is promised to exceed \(\$ 50\) million. If a person purchases \(22,957,480\) tickets in LOTTO at \(\$ 1\) per ticket (all possible combinations), isn't this a guarantee of winning the lottery? Because the probability in this situation is 1, what's wrong with doing this?

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