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Find each indicated sum. $$\sum_{i=2}^{4}\left(-\frac{1}{3}\right)^{i}$$

Short Answer

Expert verified
The sum is \( \frac{7}{243} \).

Step by step solution

01

Substitute 'i' with 2

Substituting 'i' with 2, we get \(-\frac{1}{3}^{2}\), which equals to \( \frac{1}{9} \)
02

Substitute 'i' with 3

When 'i' is 3, we get \(-\frac{1}{3}^{3}\), which equals to \(-\frac{1}{27} \)
03

Substitute 'i' with 4

Substituting 'i' with 4 results in \(-\frac{1}{3}^{4}\), which equals to \( \frac{1}{81} \)
04

Sum up the results

Adding all calculated values for \(i = 2\), \(i = 3\), and \(i = 4\) we get the total sum: \( \frac{1}{9} - \frac{1}{27} + \frac{1}{81}\).
05

Simplify the sum

The sum simplifies (using common denominator) to \( \frac{9 - 3 + 1 }{243} = \frac{7}{243} \).

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