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In Exercises 5–14, an objective function and a system of linear inequalities representing constraints are given. a. Graph the system of inequalities representing the constraints. b. Find the value of the objective function at each corner of the graphed region. c. Use the values in part ( \(b\) ) to determine the maximum value of the objective function and the values of \(x\) and \(y\) for which the maximum occurs. Objective Function Constraints $$\begin{aligned}&z=3 x-2 y\\\&\left\\{\begin{array}{l}1 \leq x \leq 5 \\\y \geq 2 \\\x-y \geq-3\end{array}\right.\end{aligned}$$

Short Answer

Expert verified
The maximum value of the objective function is 11, which occurs at the point (5, 2).

Step by step solution

01

Graph the Inequalities

To solve this exercise, we have to graph the linear inequalities namely, \(1 \leq x \leq 5\), \(y \geq 2\) and \(x-y \geq-3\). This will result in a region in the XY-plane, within which all solutions to the inequality system exist.
02

Find endpoints of the region

The next step to solving this problem would be identifying the endpoints or corners of this formed region. This is crucial because one of those points will hold the maximum value for the objective function, given this is a bounded region. For our current problem, these points would be: (1, 2), (5, 2), (2, -1) and (5, 0)
03

Compute the value of the objective function at each endpoint

Plug each of these corners (identified in Step 2) into our objective function \(z = 3x - 2y\) and compute the resulting values. Doing this will give us the values of the objective function at every corner of the region.
04

Identify the maximum value

After calculating the values of the objective function at each endpoint, look for the maximum value among them. This maximum is the solution of our problem. Alongside this maximum, the (x, y) values for which it occurs should also be reported.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

System of Linear Inequalities
Understanding a system of linear inequalities is crucial for solving optimization problems in linear programming. It involves multiple inequalities that work together to define the conditions under which the solution to a problem is deemed acceptable. In our given exercise, we encounter constraints represented by the following inequalities:
  • \(1 \leq x \leq 5\) specifies that the value of \(x\) must be between 1 and 5, inclusive.
  • \(y \geq 2\) indicates that the value of \(y\) can be any number greater than or equal to 2.
  • \(x - y \geq -3\) sets a condition relating \(x\) and \(y\) to one another.

When graphing these conditions, we look for the region where all constraints overlap. This overlapping region is known as the feasible region, and it contains all the possible solutions that satisfy the system of linear inequalities. It is the area where we will subsequently look for the optimal solution to the objective function.
Objective Function
The objective function in a linear programming problem represents the goal we're trying to achieve, such as maximizing profit or minimizing cost. It's a mathematical way to express the output we want to optimize, typically in terms of decision variables. In our exercise, the objective function is given by
\(z = 3x - 2y\).
The objective function \(z\) depends on the values of \(x\) and \(y\), which are our decision variables constrained by the system of inequalities provided. The goal is to either maximize or minimize \(z\) within the boundaries of the feasible region. To find the maximum or minimum value, we compute \(z\) at the vertices or 'corners' of the feasible region, as these are typically the points where the optimal value will be found.
Graphical Method
The graphical method is a visual approach to solving linear programming problems. It’s a particularly useful technique when dealing with two decision variables, as is the case in our exercise. The process involves several steps:
  1. Graph the individual inequalities to form the feasible region.
  2. Locate the corners of the feasible region, as these are the candidates for the optimization.
  3. Calculate the value of the objective function at each corner.
  4. Identify the corner where the objective function attains its optimal value.

By plotting the inequalities on a two-dimensional graph, we visually inspect the area of intersection, which is the feasible region. Using the graphical method not only helps to find the solution but also enhances our understanding of the relationship between different constraints and how they affect the outcome of the objective function.
Optimization
The term optimization represents the process of making the best or most effective use of resources or situations. In the context of linear programming, optimization involves finding the highest or lowest value of the objective function within the feasible region defined by a system of linear inequalities. The solution is not just any acceptable value, but the best one possible under the given constraints.
Once the feasible region is graphed, and the values of the objective function are computed for each vertex, we compare these values to ascertain the optimal solution. Optimization is the crown jewel of linear programming, enabling decision-makers to determine the most efficient and profitable course of action. In our textbook problem, the maximum value of the objective function and the corresponding coordinates \((x, y)\) give us the optimal solution where a certain condition, such as profit or cost, is optimized within the feasible region.

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Most popular questions from this chapter

A person with no more than \(\$ 15,000\) to invest plans to place the money in two investments. One investment is high risk, high yield; the other is low risk, low yield. At least \(\$ 2000\) is to be placed in the high-risk investment. Furthermore, the amount invested at low risk should be at least three times the amount invested at high risk. Find and graph a system of inequalities that describes all possibilities for placing the money in the high-and low-risk investments.

Involve supply and demand. The following models describe wages for low-skilled labor. \(\begin{array}{lcc}\text { Demand Model } & \text { Supply Model } \\ p-- 0.325 x+5.8 & p-0.375 x+3\end{array}\) a. Solve the system and find the equilibrium number of workers, in millions, and the equilibrium hourly wage. b. Use your answer from part (a) to complete this statement: If workers are paid ___ per hour, there will be ___ million available workers and ___ millions workers will be hired. c. In 2007 , the federal minimum wage was set at \(\$ 5.15\) per hour. Substitute 5.15 for \(p\) in the demand model, \(p--0.325 x+5.8,\) and determine the millions of workers employers will hire at this price. d. At a minimum wage of \(\$ 5.15\) per hour, use the supply model, \(p-0.375 x+3,\) to determine the millions of available workers. Round to one decimal place. e. At a minimum wage of \(\$ 5.15\) per hour, use your answers from parts (c) and (d) to determine how many more people are looking for work than employers are willing to hire.

Without graphing, in Exercises 73–76, determine if each system has no solution or infinitely many solutions. $$\left\\{\begin{array}{l} (x-4)^{2}+(y+3)^{2} \leq 24 \\ (x-4)^{2}+(y+3)^{2} \geq 24 \end{array}\right.$$

Compare the graphs of \(3 x-2 y>6\) and \(3 x-2 y \leq 6\) Discuss similarities and differences between the graphs.

A patient is not allowed to have more than 330 milligrams of cholesterol per day from a diet of eggs and meat. Each egg provides 165 milligrams of cholesterol. Each ounce of meat provides 110 milligrams. a. Write an inequality that describes the patient's dietary restrictions for \(x\) eggs and \(y\) ounces of meat. b. Graph the inequality. Because \(x\) and \(y\) must be positive, limit the graph to quadrant I only. c. Select an ordered pair satisfying the inequality. What are its coordinates and what do they represent in this situation?

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