/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 22 Solve each system by the additio... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve each system by the addition method. \(\left\\{\begin{array}{l}3 x+2 y-14 \\ 3 x-2 y-10\end{array}\right.\)

Short Answer

Expert verified
The solutions to the system of equations are (1, 2), (1, -2), (-1,2), (-1, -2).

Step by step solution

01

Rearrange the equations

The first rearrangement can be to make both equations look more similar. Multiply the second equation by 2: \[4x^{2}-2y^{2}=-4\]. So, now the system to solve should look like: \[\left\{\begin{array}{l} 3x^{2}-2y^{2}=-5 \\ 4x^{2}-2y^{2}=-4 \end{array}\right..\]
02

Subtract second equation from the first

Subtract the second equation from the first will remove the \( y^2 \) term. This process looks like:\[\begin{align*}(3x^{2}-4x^{2}) - (2y^{2}-2y^{2}) & = -5 - (-4) \\-x^{2} & = -1\end{align*}\]This simplifies to \(x^{2}=1\).
03

Solve for x

Now, take the square roots on both sides of \(x^{2}=1\). The solutions would be \(x=1\) and \(x=-1\).
04

Substitute the values of x into original equations

Substitute \(x=1\) into the first original equation to solve for \(y\). The equation will be \(3(1)^2-2y^2=-5\), and simplifies to \(2y^2=3+5\), so \(y^2=4\). This gives \(y=2\) and \(y=-2\). Repeat this for \(x=-1\). So all together \(x=1, y=2\) and \(x=1, y=-2\) and \(x=-1, y=2\) and \(x=-1, y=-2\) are all solutions.

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