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Evaluate or simplify each expression without using a calculator. $$ 10^{\log 53} $$

Short Answer

Expert verified
The solution for \( 10^{\log 53} \) is 53.

Step by step solution

01

Recognize the Bases

The bases for both the exponent and the logarithm are the same (which is 10). This kind of arrangement makes the problem simpler.
02

Apply The Rule

Apply the rule \( b^{\log_b x} = x \). Here, the base, \( b \), is 10, and \( x \), is 53. Thus by virtue of the rule, \(10^{\log 53}\) simplifies to 53.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponentiation and its Connection to Logarithms
Exponentiation is a fundamental mathematical operation involving two numbers: the base and the exponent, also known as the power. When a number is raised to an exponent, it means the base is multiplied by itself as many times as indicated by the exponent. For example, in the expression \(10^3\), the base is 10, and the exponent is 3, resulting in \(10 \times 10 \times 10 = 1000\). This operation is particularly useful in growth calculations and scientific notations.
Exponentiation and logarithms are closely related, as logarithms are essentially the inverse operation of exponentiation. When you have a logarithm, you're finding out the power to which a base number must be raised to get another number. For instance, \(\log_{10} 1000\) asks, "To what power must 10 be raised to equal 1000?" The answer is 3, as \(10^3 = 1000\).
Understanding this inverse relationship can simplify expressions easily when facing combined operations involving exponentials and logarithms, as they often cancel each other out.
Understanding the Change of Base Formula
The change of base formula is a logarithmic tool used to simplify calculations and make them more manageable, especially when the base isn't commonly supported by calculators or certain computations. This formula allows you to rewrite a logarithm in terms of logs of different bases. It's expressed as:
\[\log_b x = \frac{\log_k x}{\log_k b}\]
where \(b\) is the original base, \(x\) is the number you're taking the log of, and \(k\) is the new base you'd like to use. For instance, if you need to calculate \(\log_2 8\) but only have tools for calculating natural logs (base \(e\)) or decimal logs (base 10), you can use the change of base formula:
\[\log_2 8 = \frac{\log_{10} 8}{\log_{10} 2}\]
This conversion makes it easier to handle logs with unusual bases by converting them into a more familiar format. Though not directly used in the original exercise, the concept emphasizes the flexibility and versatility of logarithmic expressions.
Simplifying Expressions Involving Logs and Exponents
Simplifying expressions that involve both logarithms and exponents is all about using their properties to make the expression more manageable. An important rule to remember is the identity rule for logarithmic exponentiation: \(b^{\log_b x} = x\). This rule states that if the base of the exponent matches the base of the logarithm, you can directly simplify the expression to just \(x\).
In the given exercise, \(10^{\log 53}\), both the exponent's base and the logarithm's base are 10. Because of the identity rule, this entire expression simplifies to 53. This is because you are essentially "undoing" the operations of each other, just like subtracting a number and immediately adding the same number brings you back to the starting point.
Using rules like this allows you to cut through complexity quickly and solve expressions without exhausting step-by-step calculations, helping you to spot shortcuts and simplifications, making math both easier and more intuitive.

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Most popular questions from this chapter

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