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Find the vertical asymptotes, if any, and the values of \(x\) corresponding to holes, if any, of the graph of each rational function. $$g(x)=\frac{x+3}{x(x+4)}$$

Short Answer

Expert verified
The function \(g(x)=\frac{x+3}{x(x+4)}\) has vertical asymptotes at \(x = 0\) and \(x = -4\). There are no holes in the function's graph.

Step by step solution

01

Find the Denominator

Firstly, we need to find the denominator of the given rational function. The denominator for the function \(g(x)=\frac{x+3}{x(x+4)}\) is \(x(x+4)\)
02

Finding values that make the denominator zero

Next, we set the denominator equal to zero and solve the equation: \[x * (x + 4) = 0\] This equation is true if \(x = 0\) or \(x = -4\). These values might result in vertical asymptotes or holes, depending on whether they are also roots of the numerator expression.
03

Checking for roots in the numerator

We check if the values of \(x\) that result in a zero denominator are also roots of the numerator. In this case, \(x = -3\) makes the numerator 0, but since neither 0 nor -4 are equal to -3, these numbers do not result in holes.
04

Defining the Asymptotes

Finally, as neither of the values \(x = 0\) or \(x = -4\) result in 0 in the numerator, they are not hole-presenting values, but they are vertical asymptotes. Thus the vertical asymptotes of the function \(g(x)\) are \(x = 0\) and \(x = -4\).

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