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Solve each polynomial inequality in Exercises \(1-42\) and graph the solution set on a real number line. Express each solution set in interval notation. $$ 2 x^{2}+3 x>0 $$

Short Answer

Expert verified
The solution to the polynomial inequality \(2x^2 + 3x > 0\) is \((-1.5, 0] \cup (0, ∞)\).

Step by step solution

01

Factor the Polynomial

In order to solve the inequality \(2x^2 + 3x > 0\), it's important to first factor the polynomial to simplify the expression. Here, one can factor out \(x\) to get \(x(2x + 3) > 0\).
02

Find Critical Points

Critical points occur when the factorized polynomial equals zero. These points divide the number line into intervals. To find the critical points, set each factor equal to zero and solve for \(x\). So, \(x = 0\) and \(2x + 3 = 0\) => \(x = -1.5\).
03

Test Intervals

Now, one will test numbers from each interval to determine where the original inequality holds true. The intervals are: \((-∞, -1.5)\), \((-1.5, 0)\), and \((0, ∞)\). Select a number within each interval and substitute it into the original inequality: for example, \(x= -2, -1, 1\). By substituting, one observes that the inequality holds true for \((-1.5, 0)\) and \((0, ∞)\).
04

State the Solution in Interval Notation and Graph

The solution to the inequality is the union of the intervals where the inequality holds true. So, the solution in interval notation would be: \((-1.5, 0] \cup (0, ∞)\), indicating all the values that \(x\) could take up satisfying the inequality \(2x^2 + 3x > 0\). The number line graph would display the regions that contain these solutions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factoring Polynomials
Factoring polynomials is a crucial skill in solving polynomial inequalities. It allows us to break down complex polynomials into simpler factors, making it easier to analyze and solve inequalities. Begin by identifying the greatest common factor (GCF) of the terms in the polynomial. In the example of the polynomial \(2x^2 + 3x > 0\), the first step is to factor out \(x\), which is common in both terms. This simplifies the polynomial to \(x(2x + 3) > 0\). Understanding how to factor correctly not only simplifies the problem but also sets the stage for finding critical points, which is vital in solving inequalities. Without factoring, evaluating where a polynomial is greater than zero would be much more challenging.
  • Identify the greatest common factor.
  • Break the polynomial into simpler factors.
  • Use the factored form to solve for critical points.
Keep practicing to become comfortable with this foundational algebraic skill.
Interval Notation
Interval notation is a compact way to describe sets of numbers, especially regions of the number line. This notation is used to indicate the solution sets of inequalities. For the inequality \(2x^2 + 3x > 0\), once we find where the inequality holds, we express those intervals using interval notation. For instance, in our solution, the polynomial is greater than zero in the intervals \((-1.5, 0]\) and \((0, ∞)\). The brackets \(([\ \) and \(])\) denote inclusive (meaning the boundary point is included) or exclusive (the boundary point is not included) intervals.
  • Use round brackets, \((\mathrm{ or } )\), for open intervals, where the endpoints are not part of the solution.
  • Use square brackets, \([\mathrm{ or } ]\), for closed intervals, where the endpoints are included in the solution.
  • Combine intervals with the union symbol \(\cup\) to indicate multiple solution sets.
Interval notation provides a clear, concise way to communicate solutions.
Real Number Line
The real number line is an important tool that helps visualize the solutions of polynomial inequalities. By representing numbers as points on a line, it becomes easier to see where an inequality holds true. When solving \(2x^2 + 3x > 0\), once we find the critical points \(x = 0\) and \(x = -1.5\), they are plotted on this line. This visualization splits the number line into regions we can test for the inequality's truth. It provides a straightforward way to confirm where solutions exist by checking test points within these intervals.
  • Draw the real number line and mark the critical points found from factorization.
  • Identify and label the intervals created by these points.
  • Use the real number line to test and confirm which intervals satisfy the inequality.
Using a real number line simplifies the problem-solving process and offers a visual method to analyze polynomial inequalities.
Critical Points
Critical points in polynomial inequalities are values of \(x\) where the polynomial equals zero, creating "breaks" on the real number line. These points serve as boundaries for testing intervals where the inequality may hold true. For the inequality \(x(2x + 3) > 0\), the critical points are \(x = 0\) and \(x = -1.5\). They are found by setting each factor of the polynomial to zero. These points divide the real number line into different sections to be tested. The inequality is checked in each region to determine which satisfy the rule: that is, when they make the original inequality true.
  • Set each factor of the polynomial to zero to find the critical points.
  • Use these points to divide the number line into testable intervals.
  • Identify intervals that meet the inequality's conditions.
Critical points are fundamental in analyzing and solving polynomial inequalities, guiding us through solving these mathematical challenges.

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Most popular questions from this chapter

a. Use a graphing utility to graph \(y-2 x^{2}-82 x+720\) in a standard viewing rectangle. What do you observe? b. Find the coordinates of the vertex for the given quadratic function. c. The answer to part (b) is \((20.5,-120.5) .\) Because the leading coefficient, \(2,\) of the given function is positive, the vertex is a minimum point on the graph. Use this fact to help find a viewing rectangle that will give a relatively complete picture of the parabola. With an axis of symmetry at \(x=20.5,\) the setting for \(x\) should extend past this, so try \(\mathrm{Xmin}=0\) and \(\mathrm{Xmax}=30 .\) The setting for \(y\) should include (and probably go below) the \(y\) -coordinate of the graph's minimum y-value, so try Ymin \(=-130\). Experiment with Ymax until your utility shows the parabola's major features. d. In general, explain how knowing the coordinates of a parabola's vertex can help determine a reasonable viewing rectangle on a graphing utility for obtaining a complete picture of the parabola.

Use long division to rewrite the equation for \(g\) in the form $$\text {quotient }+\frac{\text {remainder}}{\text {divisor}}$$ Then use this form of the function's equation and transformations. $$g(x)=\frac{2 x+7}{x+3}$$

Find the slant asymptote of the graph of each rational function and b. Follow the seven-step strategy and use the slant asymptote to graph each rational function. $$f(x)=\frac{x^{2}-4}{x}$$

Follow the seven steps on page 399 to graph each rational function. $$f(x)=\frac{x-2}{x^{2}-4}$$

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