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Show that the points \(A(1,1+d), B(3,3+d),\) and \(C(6,6+d)\) are collinear (lie along a straight line) by showing that the distance from \(A\) to \(B\) plus the distance from \(B\) to \(C\) equals the distance from \(A\) to \(C\).

Short Answer

Expert verified
Yes, the given points A, B and C are collinear. The calculation has shown that AB + BC = AC, which means that these points lie along a straight line.

Step by step solution

01

Calculate the Distance from Point A to Point B

Apply the distance formula, which for two points (x1, y1) and (x2, y2), is \(d = \sqrt{(x2-x1)^2 + (y2-y1)^2}\), to find distance from Point A to B. With A(1, 1+d) and B(3, 3+d) we get distance AB = \(\sqrt{(3-1)^2+(3+d-(1+d))^2} = 2\sqrt{2}\)
02

Calculate the Distance from Point B to Point C

Apply the distance formula similarly to find distance from Point B to C. With B(3, 3+d) and C(6, 6+d) we get distance BC = \(\sqrt{(6-3)^2+(6+d-(3+d))^2} = 3\sqrt{2}\)
03

Calculate the Distance from Point A to Point C

Apply once again the distance formula to find distance from Point A to C. With A(1, 1+d) and C(6, 6+d) we get distance AC = \(\sqrt{(6-1)^2+(6+d-(1+d))^2} = 5\sqrt{2}\)
04

Show That AB + BC = AC

Add the distances from A to B and B to C, and show that it is equal to the distance from A to C. Therefore, 2\sqrt{2} + 3\sqrt{2} = 5\sqrt{2}
05

Conclusion

Since AB + BC equals AC, we can conclude that the points A, B, and C lie along a straight line, meaning they are collinear as per the definition of collinear points.

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