/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 78 Give an example of a circle's eq... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 2: Problem 78

Give an example of a circle's equation in standard form. Describe how to find the center and radius for this circle.

Short Answer

Expert verified
The standard form equation of a circle given in this example is \( (x - 3)^2 + (y - 5)^2 = 16 \). The center of the circle is at \( (3,5) \) and its radius is 4.

Step by step solution

01

Define circle's standard form equation

First, you need to understand that the standard form for the equation of a circle is \( (x - h)^2 + (y - k)^2 = r^2 \), where \( (h,k) \) are the coordinates of the center and \( r \) is the radius
02

Give an example of a circle's equation in standard form

Let's consider a circle with the following standard form equation: \( (x - 3)^2 + (y - 5)^2 = 16 \)
03

Identify circle's center and radius

From this equation, we can see that the center \( (h,k) \) is \( (3,5) \) because of the expressions \( (x - 3) \) and \( (y - 5) \). The radius \( r \) can be found by taking the square root of 16, so \( r = 4 \)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Begin by graphing the absolute value function, \(f(x)-|x| .\) Then use transformations of this graph to graph the given function. $$ g(x)--2|x+4|+1 $$

$$\text { Solve for } y: 3 x+2 y-4=0$$

Begin by graphing the standard cubic function, \(f(x)-x^{3} .\) Then use transformations of this graph to graph the given function. $$ r(x)-(x-3)^{3}+2 $$

Begin by graphing the standard cubic function, \(f(x)-x^{3} .\) Then use transformations of this graph to graph the given function. $$ h(x)-\frac 12 x^{3} $$

Determine whether each statement makes sense or does not make sense, and explain your reasoning. I noticed that the difference quotient is always zero if \(f(x)=c,\) where \(c\) is any constant.
See all solutions

Recommended explanations on Math Textbooks

Geometry

Read Explanation

Decision Maths

Read Explanation

Probability and Statistics

Read Explanation

Mechanics Maths

Read Explanation

Applied Mathematics

Read Explanation

Theoretical and Mathematical Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.