/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 57 Complete the square and write th... [FREE SOLUTION] | 91Ó°ÊÓ

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Complete the square and write the equation in standard form. Then give the center and radius of each circle and graph the equation. $$x^{2}+y^{2}+8 x-2 y-8=0$$

Short Answer

Expert verified
The equation in standard form is \( (x + 4)^{2} + (y - 1)^{2} = 25 \). Center of the circle is (-4, 1) and the radius is 5.

Step by step solution

01

Group the x and y terms together

First, let's group the x and y terms in the equation together. The equation \( x^{2}+y^{2}+8 x-2 y-8=0 \) becomes \( (x^{2} + 8x) + (y^{2} - 2y) = 8 \)
02

Complete the square for x and y

Completing the square involves adding the square of half of the coefficient of x and y to both sides. This gives the equation \( (x^{2} + 8x + 16) + (y^{2} - 2y + 1) = 8 + 16 + 1 \), which simplifies to \( (x + 4)^{2} + (y - 1)^{2} = 25 \)
03

Identify the center and radius of the circle

In the equation \( (x - h)^{2} + (y - k)^{2} = r^{2} \), (h, k) are the coordinates of the center of the circle, and r is the radius. From our equation \( (x + 4)^{2} + (y - 1)^{2} = 25 \), we can deduce that the center of the circle is (-4, 1) and the radius is 5
04

Graph the equation

When graphing the equation, start by marking the center of the circle at the point (-4, 1). Then, draw a circle with radius 5 around this point.

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