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91Ó°ÊÓ

Find the distance between each pair of points. If necessary, round answers to two decimals places. $$(3.5,8.2)\( and \)(-0.5,6.2)$$

Short Answer

Expert verified
The distance between the points (3.5, 8.2) and (-0.5, 6.2) is approximately 4.47 units.

Step by step solution

01

Identify the coordinates

Identify and label the coordinates. Let's label them as follows: \((x_1, y_1) = (3.5, 8.2)\) and \((x_2, y_2) = (-0.5, 6.2)\)
02

Plug the values into the formula

Now, plug these values into the distance formula: \(d = \sqrt{(-0.5-3.5)^2 + (6.2-8.2)^2}\)
03

Calculate the square of each number

Calculate the squares inside brackets: \(d = \sqrt{(-4)^2 + (-2)^2}= \sqrt{16+4}\)
04

Sum up and take the square root

Now sum up these squares and then take the square root: \(d = \sqrt{20} = 4.47\) (rounded to two decimal places).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coordinate Geometry Basics
Coordinate geometry, also known as analytic geometry, deals with defining and representing geometric shapes in a numerical way. This system is based on a coordinate plane, which is a two-dimensional space defined by a horizontal axis (x-axis) and a vertical axis (y-axis). Any point in this space can be described using a pair of coordinates, like \(x,y\), where 'x' represents the position along the x-axis, and 'y' represents the position along the y-axis.
This allows us to precisely locate points and measure distances between them, leading to a deeper understanding of spatial relationships. In the problem given, the points (3.5, 8.2) and (-0.5, 6.2) are defined in this coordinate system. The goal is to find the distance between these two points using coordinate geometry principles.
Understanding Distance Calculation
Finding the distance between two points on a plane involves using the distance formula, an essential tool in coordinate geometry. The distance formula is derived from the Pythagorean theorem and is written as:
\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]
This formula calculates the straight-line distance (also known as Euclidean distance) between two points by summing the squares of the differences in their x and y coordinates, then taking the square root of that sum.
  • The x-coordinates from each point are subtracted, squared, and added to the square of the difference in the y-coordinates.
  • Finally, the square root of this total gives the final distance.

This method ensures accuracy and consistency in measuring distances, which is especially useful in fields like physics and engineering.
Rounding Decimals
After calculating a numerical answer, it's often necessary to round the result to make it more readable or to meet specific precision requirements. In the context of the given problem, the distance is calculated to be \[ \sqrt{20} \]. When you compute this value, it equals approximately 4.4721359. For practical purposes, we might need to round this to a number with fewer decimal places, such as two decimal places.
  • To round to two decimal places, look at the third decimal place.
  • If it's 5 or greater, you round the second decimal place up. If it's less than 5, you keep the second decimal place as is.

For \sqrt{20}\, the third decimal is 2, which means the correct rounded result to two decimal places is 4.47. Rounding helps simplify data presentation without significantly losing accuracy.

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Most popular questions from this chapter

a. Use a graphing utility to graph \(f(x)=x^{2}+1\) b. Graph \(f(x)=x^{2}+1, g(x)=f(2 x), h(x)=f(3 x),\) and \(k(x)=f(4 x)\) in the same viewing rectangle. c. Describe the relationship among the graphs of \(f, g, h\) and \(k,\) with emphasis on different values of \(x\) for points on all four graphs that give the same \(y\) -coordinate. d. Generalize by describing the relationship between the graph of \(f\) and the graph of \(g,\) where \(g(x)=f(c x)\) for \(c>1\) e. Try out your generalization by sketching the graphs of \(f(c x)\) for \(c=1, c=2, c=3,\) and \(c=4\) for a function of your choice.

Begin by graphing the standard cubic function, \(f(x)-x^{3} .\) Then use transformations of this graph to graph the given function. $$ h(x)-\frac 12(x-3)^{3}-2 $$

In Tom Stoppard's play Arcadia , the characters dream and talk about mathematics, including ideas involving graphing. composite functions, symmetry, and lack of symmetry in things that are tangled, mysterious, and unpredictable. Group members should read the play. Present a report on the ideas discussed by the characters that are related to concepts that we studied in this chapter. Bring in a copy of the play and read appropriate excerpts.

Begin by graphing the standard cubic function, \(f(x)-x^{3} .\) Then use transformations of this graph to graph the given function. $$ r(x)-(x-3)^{3}+2 $$

Begin by graphing the standard cubic function, \(f(x)-x^{3} .\) Then use transformations of this graph to graph the given function. $$ g(x)-x^{3}-2 $$

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