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Begin by graphing the standard cubic function, \(f(x)-x^{3} .\) Then use transformations of this graph to graph the given function. $$ h(x)-\frac 1 2(x-2)^{3}-1 $$

Short Answer

Expert verified
To transform the graph of the function \(f(x) = x^3\) to match the function \(h(x) = -\frac{1}{2}(x - 2)^3 - 1\), we perform a horizontal shift of 2 units to the right, a vertical shift of 1 unit downwards, and a vertical stretch with a factor of -0.5.

Step by step solution

01

Graph the Standard Cubic Function

Start by graphing the basic cubic function \(f(x) = x^{3}\). This function increases rapidly for \(x > 0\) and decreases rapidly for \(x < 0\). It goes through the origin (0,0) because \(0^{3} = 0\).
02

Horizontal Transformation

The expression inside the parentheses, \(x-2\), signifies horizontal shift. Subtracting from \(x\) causes the function to shift to the right by 2 units. This moves the entire graph of \(f(x) = x^{3}\) two units to the right. Now the function graph will cross the point (2,0) instead of the origin.
03

Vertical Transformation

The -1 outside the function represents the vertical shift. This causes a downward shift of the graph by 1 unit. So every point on the graph is reduced by 1 on the y-axis.
04

Vertical Stretch

The function \(h(x) = -\frac{1}{2}(x-2)^{3}-1\) has a leading coefficient of \(-\frac{1}{2}\). This will stretch and flip the original graph. A negative coefficient will reflect the graph over the x-axis, and the fraction \(\frac{1}{2}\) will compress the graph vertically. This makes the increase and decrease half as steep as before.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Standard Cubic Function
A standard cubic function takes the form of \(f(x) = x^3\). Its graph is characterized by a distinctive 'S' shape, presenting symmetry about the origin point \((0, 0)\).

This function is important as a building block for more complex cubic functions. It serves as the starting point for graph transformations. When graphed, it exhibits an increasing behavior for \(x > 0\) and a decreasing behavior for \(x < 0\), passing through the origin where \(f(0) = 0\).

One helpful aspect worth remembering is that, unlike quadratic functions, which always turn at their vertex, cubic functions do not have a maximum or minimum point; they continue on infinitely towards positive or negative infinity. Therefore, their end behavior is such that as \(x\) approaches infinity, \(f(x)\) does too, and the same applies as \(x\) approaches negative infinity.
Applying a Horizontal Shift Transformation
To comprehend the horizontal shift transformation, it's critical to focus on the changes within the parentheses of the function expression. Specifically, in \(h(x) = (x - 2)^3\), the \(x - 2\) indicates a shift to the right by 2 units.

This transformation slides every single point on the graph of our standard cubic function horizontally by 2 spaces. If the transformation were \((x + h)\), we would instead move the graph to the left by \(h\) units. Keeping the direction of the shift aligned with the sign—left for positive, right for negative—is a helpful tip for students.

Following this step precisely ensures the transformed graph will maintain the same shape but will now intersect the x-axis at \((2, 0)\) instead of the origin. This can also be thought of as if you're picking up the entire function and physically moving it horizontally without altering its shape.
Understanding Vertical Shift Transformation
A vertical shift transformation in a cubic function is indicated by an addition or subtraction at the very end of the function's formula. For instance, in \(h(x) = \frac{1}{2}(x - 2)^3 - 1\), the \(-1\) tells us to move every point on the graph down by 1 unit.

This downward translation is like adjusting the baseline of the entire graph. If the number were positive, we would be moving the graph up instead. Vertical shifts do not change the shape or the orientation of the graph; they simply adjust its position along the y-axis.

A practical way of visualizing this shift is to imagine that the x-axis stays fixed, and the whole curve is either hoisted up or pressed down, depending on the positive or negative nature of the vertical shift.
Decoding Vertical Stretch Factors
Vertical stretches and compressions are transformations that change the 'tightness' or 'steepness' of the graph. When examining the function \(h(x) = -\frac{1}{2}(x - 2)^3 - 1\), the coefficient of \(-\frac{1}{2}\) before the cubic term indicates two operations: a reflection and a vertical compression.

The negative sign means the graph is reflected over the x-axis, essentially flipping it upside down. This transformation is crucial when depicting real-world situations like projectile motion when an object's path reverses direction.

Moreover, the absolute value of the fraction \(|\frac{1}{2}|\) results in a vertical 'compression.' This makes the graph less steep than the standard cubic function. Unlike a 'stretch,' which would elongate the graph vertically, a compression 'squishes' it.

The combination of these transformations can drastically change the original function's appearance. Yet, by breaking down each step, as we have done, students can more clearly follow the function's evolution and accurately sketch the new graph.

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Most popular questions from this chapter

Group members who have cellphone plans should describe the total monthly cost of the plan as follows: ______ per month buys _______minutes. Additional time costs $________ per minute. (For simplicity, ignore other charges.) The group should select any three plans, from "basic" to "premier." For each plan selected, write a piecewise function that describes the plan and graph the function. Graph the three functions in the same rectangular coordinate system. Now examine the graphs. For any given number of calling minutes, the best plan is the one whose graph is lowest at that point. Compare the three calling plans. Is one plan always a better deal than the other two? If not, determine the interval of calling minutes for which each plan is the best deal.

Furry Finances A pet insurance policy has a monthly rate that is a function of the age of the insured dog or cat. For pets whose age does not exceed \(4,\) the monthly cost is \(\$ 20\). The cost then increases by \(\$ 2\) for each successive year of the pet's age. $$\begin{array}{|c|c|}\hline\hline\text { Age Not Exceeding } & \text { Monthly Cost } \\\\\hline 4 & \$ 20 \\\5 & \$ 22 \\\6 & \$ 24\end{array}$$ The cost schedule continues in this manner for ages not exceeding \(10 .\) The cost for pets whose ages exceed 10 is S40. Use this information to create a graph that shows the monthly cost of the insurance, \(f(x)\), for a pet of age \(x,\) where the function's domain is \([0,14]\).

Begin by graphing the standard cubic function, \(f(x)-x^{3} .\) Then use transformations of this graph to graph the given function. $$ h(x)-\frac 12 x^{3} $$

Use a graphing utility to graph each function. Use a \([-5,5,1]\) by \([-5,5,1]\) viewing rectangle. Then find the intervals on which the function is increasing, decreasing, or constant. $$h(x)=|x-2|+|x+2|$$

Begin by graphing the cube root function, \(f(x)-\sqrt[3]{x} .\) Then use transformations of this graph to graph the given function. $$ h(x)-\frac{1}{2} \sqrt[3]{x-2} $$

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