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Add or subtract as indicated. $$\frac{3 x}{x-3}-\frac{x+4}{x+2}$$

Short Answer

Expert verified
The result of the operation \(\frac{3x}{x-3} - \frac{x+4}{x+2}\) is \(\frac{(2x-3)(x+4)}{(x-3)(x+2)}\).

Step by step solution

01

Identify the denominators

The denominators of the fractions are \(x-3\) and \(x+2\). In order to add or subtract fractions, they must have a common denominator.
02

Find the common denominator

To find a common denominator, the denominators can be multiplied together to get \((x-3) * (x+2)\) as the common denominator.
03

Rewrite the fractions with the common denominator

Rewrite the fractions such that they both have the common denominator. This gives \(\frac{3x * (x+2)}{(x-3)*(x+2)} - \frac{(x+4) * (x-3)}{(x-3)*(x+2)}\).
04

Expand the numerators

Expand the numerators: \(\frac{3x*x+6x}{(x-3)*(x+2)} - \frac{x*x -3x+12}{(x-3)*(x+2)}\) which simlifies to \(\frac{3x^2+6x}{x^2 -x -6} - \frac{x^2 -3x +12}{x^2 -x -6}\).
05

Subtract the fractions

Now the fractions can be subtracted since they have the same denominator. This gives \(\frac{3x^2+6x - (x^2 -3x +12)}{x^2 -x -6}\) which simplifies to \(\frac{2x^2+9x -12}{x^2 -x -6}\).
06

Factorize the numerator and denominator, if possible

In this case, the numerator and denominator can be factorized, giving \(\frac{(2x-3)(x+4)}{(x-3)(x+2)}\).

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