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Chapter 0: Problem 23

Find each product. $$(3 x+5)(2 x+1)$$

Short Answer

Expert verified
The product of the two binomials \(3x+5\) and \(2x+1\) is \(6x^2 + 13x + 5\).

Step by step solution

01

Distribute the first term of the first binomial

Distribute the first term (3x) of the first binomial (3x + 5) over the second binomial (2x + 1). Apply the distributive rule: a*(b+c) = a*b + a*c. Here, a is 3x, b is 2x and c is 1. This results in (3x * 2x) + (3x * 1). Calculate the value of these operations to get \(6x^2\) and \(3x\).
02

Distribute the second term of the first binomial

Next, distribute the second term (5) of the first binomial (3x + 5) over the second binomial (2x + 1). Using the distributive rule again, this results in (5 * 2x) + (5 * 1). Calculate these operations to get \(10x\) and \(5\).
03

Combine like terms

After performing steps 1 and 2, four terms are obtained: \(6x^2, 3x, 10x\) and \(5\). Combine the terms that have the same variable, i.e. \(3x\) and \(10x\). This results in \(6x^2 + 13x + 5\).

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Most popular questions from this chapter

In Exercises 132鈥�135, determine whether each statement makes sense or does not make sense, and explain your reasoning. There are many exponential expressions that are equal to \(36 x^{12},\) such as \(\left(6 x^{6}\right)^{2},\left(6 x^{3}\right)\left(6 x^{9}\right), 36\left(x^{3}\right)^{9},\) and \(6^{2}\left(x^{2}\right)^{6}\)

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