/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 56 Write a probability word problem... [FREE SOLUTION] | 91Ó°ÊÓ

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Write a probability word problem whose answer is one of the following fractions: \(\frac{1}{6}\) or \(\frac{1}{4}\) or \(\frac{1}{3}\)

Short Answer

Expert verified
Three different probability problems were created with the respective solutions of \(\frac{1}{6}\), \(\frac{1}{4}\), and \(\frac{1}{3}\). Though these problems were formulated independently, they could be combined into a single complex problem if desired.

Step by step solution

01

Formulate a probability problem with the answer \(\frac{1}{6}\)

Imagine you have a six-sided die (standard die). The die is fair, which means all sides are equally likely to come up when rolled. When rolled, what is the probability that the number 1 appears?
02

Calculation for problem in Step 1

Since there is only one face with the number 1, and there are six faces in total, the probability is therefore \(\frac{1}{6}\), which is the desired outcome.
03

Formulate a probability problem with the answer \(\frac{1}{4}\)

Let's take the case where you have a bag containing 4 marbles: 1 blue, 1 green, 1 red, and 1 yellow. If you draw one marble randomly from the bag, what would be the probability that the marble drawn is blue?
04

Calculation for problem in Step 3

Since there is only one blue marble, and there are four marbles in total, the probability is therefore \(\frac{1}{4}\), which is the desired outcome.
05

Formulate a probability problem with the answer \(\frac{1}{3}\)

Imagine you have a box containing 3 balls: 1 white, 1 black, and 1 silver. If you choose one ball randomly from the box, what would be the probability that the ball chosen is silver?
06

Calculation for problem in Step 5

Since there is only one silver ball, and there are three balls in total, the probability is therefore \(\frac{1}{3}\), which is the desired outcome.

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