/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 41 Find each indicated sum. $$\su... [FREE SOLUTION] | 91Ó°ÊÓ

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Find each indicated sum. $$\sum_{i=1}^{5} \frac{i !}{(i-1) !}$$

Short Answer

Expert verified
The result of the sum \(\sum_{i=1}^{5} \frac{i !}{(i-1) !}\) is 15.

Step by step solution

01

Parsing the series

The provided series is \(\sum_{i=1}^{5} \frac{i !}{(i-1) !}\). In this summation, \(i\) takes on values from 1 to 5 and for each \(i\), the term \(\frac{i !}{(i-1) !}\) is calculated and added to the sum.
02

Understanding Factorial Division

They key to solving this exercise is to understand that by definition \(i ! = i * (i-1) *\dots*2*1\), so \(\frac{i !}{(i-1) !} = i\).
03

Substituting and Calculating

After substituting the expression obtained in the previous step the series becomes \(\sum_{i=1}^{5} i\), resulting in the result being \(1 + 2 + 3 + 4 + 5 = 15\).

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