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Chapter 6: Problem 55

What is the difference between Gaussian elimination and Gauss-Jordan elimination?

Short Answer

Expert verified
Gaussian elimination transforms a system of linear equations into an upper triangular matrix which can then be solved through back substitution, while Gauss-Jordan elimination transforms the system into reduced row echelon form, from which the solution can be directly read. Gauss-Jordan elimination generally requires more computational work than Gaussian elimination.

Step by step solution

01

Understanding Gaussian Elimination

Gaussian elimination, also known as row reduction, is a method used to solve a system of linear equations. In Gaussian elimination, the primary goal is to convert the system into an upper triangular matrix. From this form, it becomes easier to find the solutions through back substitution. The process involves three types of elementary row operations: Swapping two rows, multiplying a row by a non-zero scalar, and adding/subtracting a row to/from another row.
02

Understanding Gauss-Jordan Elimination

The Gauss-Jordan elimination is an extension of Gaussian elimination. The goal here is not just an upper triangular matrix, but what is known as a reduced row echelon form (rref). This matrix form has leading coefficients as 1 and the elements above and below them as 0. This form eliminates the need for back substitution as every variable stands alone in an equation, making the solution more straightforward. The same elementary row operations are performed as in Gaussian elimination, but the process goes a step further to master the zeros both above and below the leading coefficients.
03

Comparing the Two Methods

The main difference between these two methods is the form of the matrix they result in. Gaussian elimination results in an upper triangular matrix, requiring back substitution to solve the system, while Gauss-Jordan elimination results in a reduced row echelon form for the system, from which the solution can be directly read off. It's also worth noting that Gauss-Jordan elimination generally requires more computational work than Gaussian elimination.

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Most popular questions from this chapter

In Exercises \(9-16,\) find: a. \(A+B\) b. \(A-B\) c. \(-4 A\) d. \(3 A+2 B\) $$ A=\left[\begin{array}{ll} 1 & 3 \\ 3 & 4 \\ 5 & 6 \end{array}\right], \quad B=\left[\begin{array}{rr} 2 & -1 \\ 3 & -2 \\ 0 & 1 \end{array}\right] $$

In applying Cramer's rule, what does it mean if \(D=0 ?\)

In Exercises \(1-4\) a. Give the order of each matrix. b. If \(A=\left[a_{i j}\right],\) identify \(a_{32}\) and \(a_{23}\) or explain why identification is not possible. $$ \left[\begin{array}{rrrr} -4 & 1 & 3 & -5 \\ 2 & -1 & \pi & 0 \\ 1 & 0 & -e & \frac{1}{5} \end{array}\right] $$

Use Cramer's rule to solve each system or to determine that the system is inconsistent or contains dependent equations. $$ \begin{aligned}&2 x=3 y+2\\\&5 x=51-4 y\end{aligned} $$

In Exercises \(27-36,\) find (if possible): \(\begin{array}{llll}\text { a. } A B & \text { and } & \text { b. } B A\end{array}\) $$ A=\left[\begin{array}{l} -1 \\ -2 \\ -3 \end{array}\right], \quad B=\left[\begin{array}{lll} 1 & 2 & 3 \end{array}\right] $$
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