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Graph the solution set of each system of inequalities or indicate that the system has no solution. $$ \begin{aligned}&x \leq 2\\\&y \geq-1\end{aligned} $$

Short Answer

Expert verified
The solution set of the system of inequalities is represented by the area on the graph that is to the left of the line \(x = 2\) and above the line \(y = -1\).

Step by step solution

01

Graphing the first inequality

First, plot the line \(x = 2\). Because the inequality is \(x \leq 2\), we know that the solution includes the line \(x = 2\) and everything to the left of it, as this represents all values of x that are less than or equal to 2. Hence, we shade everything to the left of the line.
02

Graphing the second inequality

Next, plot the line \(y = -1\). Because the inequality is \(y \geq -1\), we know that the solution includes the line \(y = -1\) and everything above it, as these are the y values that are greater than or equal to -1. So we shade everything above this line.
03

Finding the intersection

The solution set of the system of inequalities is the intersection of the solution sets of the individual inequalities. This is represented by the area that is shaded for both inequalities on the graph. In this case, it is the area to the left of the line \(x = 2\) and above the line \(y = -1\). Hence, this area is the solution set for the given system of inequalities.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inequality Graphing
Graphing an inequality involves plotting a boundary line on the coordinate plane and shading a region to represent all the possible solutions that satisfy the inequality. For example, let's consider the inequality \(x \leq 2\). To graph this inequality, you would first draw the vertical line \(x = 2\), which would serve as the boundary.

The inequality indicates that we're interested in all the values less than or equal to 2; therefore, the region to the left of this vertical line (including the line itself, since it's \(\leq\) and not \(<\)) is shaded. Similarly, for the inequality \(y \geq -1\), the horizontal line \(y = -1\) is drawn, and the region above this line is shaded because \(y\) values are larger than or equal to -1.

Graphing inequalities requires attention to the type of line used for the boundary as well. A solid line is used to represent \(\leq\) or \(\geq\) since the points on the line are included in the solutions, while a dashed line is used for \(<\) or \(>\) since the points on the line are not included.
Solution Set of Inequalities
The solution set of a system of inequalities is the region of the plane where the shaded areas of all individual inequalities overlap. In essence, it is the set of all possible points \((x, y)\) that satisfy all the inequalities in the system simultaneously. Referencing our exercise, the solution set is found at the intersection of the shaded regions for each inequality.

The solution set can be visualized as the common shaded region. For the system including \(x \leq 2\) and \(y \geq -1\), the solution set is the area to the left of or on the line \(x = 2\) and above or on the line \(y = -1\). When graphed, it is the region that is doubly shaded and represents the set of coordinates that adhere to both conditions at once. It's often helpful to test points within the shaded region to verify that they meet all constraints of the inequalities.
Graphing Linear Inequalities
Graphing linear inequalities is similar to graphing linear equations, but instead of a line representing all the solutions, a half-plane is identified as the solution set. For each linear inequality, start by graphing the corresponding linear equation as if the inequality symbol were an equal sign.

For instance, with the inequality \(y \geq -1\), graph the line \(y = -1\) first. Since this is an inequality rather than an equation, the next step is to choose which side of the line represents the solution set. If the inequality is greater than (\(>\)) or greater than or equal to (\(\geq\)), you shade above the line. Conversely, if the inequality is less than (\(<\)) or less than or equal to (\(\leq\)), you shade below the line.

Identifying Solid or Dashed Lines

Remember, use a solid line for inequalities including \(\leq\) or \(\geq\), indicating that points on the line satisfy the inequality. Use a dashed line for strict inequalities, \(<\) or \(>\), where the points on the line are not part of the solution set.

The key to graphing a system of linear inequalities is to individually plot and shade each inequality and then determine the overlapped region where both conditions are true.

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Most popular questions from this chapter

In Exercises \(31-42,\) solve by the method of your choice. Identify systems with no solution and systems with infinitely many solutions, using set notation to express their solution sets. \(2 x=3 y+4\) \(4 x=3-5 y\)

Exercises \(47-50\) describe a number of business ventures. For each exercise, a. Write the cost function, \(C\). b. Write the revenue function, \(R\) c. Determine the break-even point. Describe what this means. You invest in a new play. The cost includes an overhead of \(\$ 30,000,\) plus production costs of \(\$ 2500\) per performance. A sold-out performance brings in \(\$ 3125\). (In solving this exercise, let \(x\) represent the number of sold-out performances.)

The weekly demand and supply models for a particular brand of scientific calculator for a chain of stores are given by the demand model \(N=-53 p+1600,\) and the supply model \(N=75 p+320 .\) In these models, \(p\) is the price of the calculator and \(N\) is the number of calculators sold or supplied each week to the stores. a. How many calculators can be sold and supplied at \(\$ 12\) per calculator? b. Find the price at which supply and demand are equal. At this price, how many calculators of this type can be supplied and sold each week?

At a price of \(p\) dollars per ticket, the number of tickets to a rock concert that can be sold is given by the demand model \(N=-25 p+7500 .\) At a price of \(p\) dollars per ticket, the number of tickets that the concert's promoters are willing to make available is given by the supply model \(N=5 p+6000\) a. How many tickets can be sold and supplied for \(\$ 40\) per ticket? b. Find the ticket price at which supply and demand are equal. At this price, how many tickets will be supplied and sold?

In Exercises \(19-30,\) solve each system by the addition method. \(\begin{aligned} x+2 y &=2 \\\\-4 x+3 y &=25 \end{aligned}\)

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