/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 Find the quadratic function \(y=... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the quadratic function \(y=a x^{2}+b x+c\) whose graph passes through the given points. $$(1,3),(3,-1),(4,0)$$

Short Answer

Expert verified
The quadratic function is \(y = x^2 - 4x + 6\).

Step by step solution

01

Formation of Equations

The quadratic function is defined as \(y = ax^2 + bx + c\). By inserting the x and y values from the three points given, the following equations are obtained: \From \((1,3)\), we get \(3 = a + b + c\),\From \((3,-1)\), we get \(-1 = 9a + 3b + c\),\From \((4,0)\), we get \(0 = 16a + 4b + c\).
02

Solving System of Equations

By subtracting the first equation from the second and third equations, the system is simpler :\After subtraction, two new equations are obtained: \\(9a + 3b - a - b = -4 \Rightarrow 8a + 2b = -4 \), and \\(16a + 4b - a - b = -3 \Rightarrow 15a + 3b = -3 \).\These are easier to solve. Dividing the first one by 2 and the second one by 3 gives: \\(4a + b = -2\), and \\(5a + b = -1\).\Subtracting these two gives \(-a = -1 \Rightarrow a = 1 \). Inserting \(a = 1\) into \(4a + b = -2 \) gives \(b = -4\). Inserting \(a = 1\) and \(b = - 4\) into the first original equation \(3 = a + b + c \) gives \(c = 6\).
03

Finding the Quadratic Function

Inserting \(a = 1\), \(b = -4\), and \(c = 6\) back into the original equation \(y = ax^2 + bx + c\) gives the specific quadratic function \(y = x^2 - 4x + 6\).

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