/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 22 Find the quadratic function \(y=... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the quadratic function \(y=a x^{2}+b x+c\) whose graph passes through the given points. $$(-2,7),(1,-2),(2,3)$$

Short Answer

Expert verified
The quadratic function is: \(y = 4x^{2} + x - 7\)

Step by step solution

01

Substitute the points into the quadratic function

Start by substituting the given points into the equation for \(y\). This will create a system of three equations.\n1) Substituting the point \((-2,7)\) into the equation gives: \(7 = a(-2)^2 + b(-2) + c\). Simplify this equation to: \(7 = 4a - 2b + c\).\n2) Substituting the point \((1,-2)\) into the equation gives: \(-2 = a(1)^2 + b(1) + c\). Simplify this equation to: \(-2 = a + b + c\).\n3) Substituting the point \((2,3)\) into the equation gives: \(3 = a(2)^2 + b(2) + c\). Simplify this equation to: \(3 = 4a + 2b + c\).
02

Solve the system of equations

Now solve this system of linear equations for \(a\), \(b\), and \(c\). To make it easier, try to subtract second equation from the first and third equations: \n1) Subtracting the second equation from the first gives: \(9 = 3a - 3b\). Simplify it further to get \(a - b = 3\). \n2) Subtracting the second equation from the third gives: \(5 = 3a + b\).
03

Find the solution for a and b

Now we have system of two equations: \n1) \(a - b = 3\) \n2) \(a + b = 5\). Adding these two equations together gives \(2a = 8\) which simplifies to \(a = 4\). Substituting \(a = 4\) into the second equation gives \(b = 1\).
04

Find the value of c

Substitute \(a = 4\) and \(b = 1\) into one of the initial three equations to solve for \(c\). We will use equation \(-2 = a + b + c\), hence \(c = -2 - a - b = -2 - 4 - 1 = -7\).

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