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Solve each exponential equation in Exercises \(1-26\) Express the solution set in terms of natural logarithms. Then use a calculator to obtain a decimal approximation, correct to two decimal places, for the solution. $$7^{2 x-1}=3^{x+2}$$

Short Answer

Expert verified
The solution to the exponential equation is \( x = 1.29 \), correct to two decimal places.

Step by step solution

01

Express the equation in logarithmic form

We will start by taking the natural logarithm of both sides of the equation. Let's denote the natural logarithm of a number as ln. So, applying the logarithm on both sides of the given equation \(7^{2x - 1} = 3^{x + 2}\), we have \( ln(7^{2x-1}) = ln(3^{x + 2})\)
02

Use the properties of logarithms

We can use the properties of logarithms to simplify the equation: if \( b = a^x \), then \( x = ln(b)/ln(a) \). So, we can bring the exponents down using the properties of logarithms to get \( (2x - 1)ln(7) = (x + 2)ln(3) \).
03

Solve for \( x \)

Now we can solve for \( x \). First distribute the logarithm on the left, and then \ group all terms involving \( x \) on one side to get: \(2xln(7) - ln(7) = xln(3) + 2ln(3)\). By grouping all the \( x \) terms together on one side and constants on the other side, we get: \(2xln(7) - xln(3) = 2ln(3) + ln(7)\). By factoring out \( x \) from the left side, we get \(x(2ln(7) - ln(3)) = 2ln(3) + ln(7)\). Finally, divide both sides by \(2 ln(7) - ln(3)\) to solve for \(x\): \( x = \frac{2ln(3) + ln(7)}{2ln(7) - ln(3)}\).
04

Get the decimal approximation

Now use a calculator to obtain a decimal approximation, correct to two decimal places, for the solution. After calculating, the value of \( x \) comes out to be approximately 1.29.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Natural Logarithms
Natural logarithms are a type of logarithm, which is a mathematical function that helps us solve equations where the unknown appears as the exponent of a number. Specifically, natural logarithms use the number e as their base, where e is approximately equal to 2.71828. It's an important mathematical constant used often in calculus and complex mathematics.

The natural logarithm of a number x is usually denoted as \( \ln(x) \). The defining property of natural logarithms is that \( \ln(e) = 1 \). Natural logarithms convert multiplicative processes into additive ones, which is extremely useful when dealing with exponential growth or decay.

In the context of solving exponential equations, the natural logarithm can be used to 'bring down' the exponent in an equation, as seen in the example where \( \ln(7^{2x-1}) \) becomes \( (2x-1)\ln(7) \). This property makes it much easier to solve equations that would otherwise be difficult to manage.
Properties of Logarithms
Logarithms have unique properties that make them handy tools for solving equations, especially when dealing with powers. One of these is the power rule, which allows us to take an exponent and transform it into a multiplication outside the logarithm. This is precisely what is done when \( ln(7^{2x-1}) \) becomes \( (2x-1)ln(7) \).

Another property is the change of base formula which allows us to convert from one logarithmic base to another, though this property isn't directly used in our example, it's important to know it exists. Also, when two logarithmic terms with the same base are subtracted or added, they can be combined or separated into the logarithm of the division or multiplication of their inputs, respectively.

These properties, when applied correctly, simplify complex equations and make them solvable by standard algebraic techniques. For instance, in our textbook exercise, after using logarithm properties, the equation reduces to a form where \( x \) can be isolated and solved for.
Exponential Equation Solution
Exponential equations can often be intimidating because the variable we're trying to solve for is in the exponent. However, by utilizing the properties of logarithms, especially natural logarithms, we can bring the variable down to 'ground level', so to speak. From there, we can use algebraic techniques to solve for the variable.

To solve for \( x \) in our exponential equation, we used logarithms to linearize the equation. Once the exponents were brought down and we had a linear equation, it was simply a matter of manipulating the equation to isolate the variable \( x \). The final step was to divide both sides by the coefficient of \( x \) to find its precise value.

After the exact logarithmic solution for \( x \) is found, it is often useful to find a decimal approximation to get a concrete understanding of the solution. This is done using a calculator, showcasing the importance of both the analytical and numerical aspects of mathematics in solving real-world problems.

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Most popular questions from this chapter

The formula $$ t=\frac{1}{c}[\ln A-\ln (A-N)] $$ describes the time, \(t,\) in weeks, that it takes to achieve mastery of a portion of a task, where \(A\) is the maximum learning possible, \(N\) is the portion of the learning that is to be achieved, and \(c\) is a constant used to measure an individual's learning style. a. Express the formula so that the expression in brackets is written as a single logarithm. b. The formula is also used to determine how long it will take chimpanzees and apes to master a task. For example, a typical chimpanzce learning sign language can master a maximum of 65 signs. Use the form of the formula from part (a) to answer this question: How many weeks will it take a chimpanzee to master 30 signs if \(c\) for that chimp is \(0.03 ?\)

In Exercises \(1-40,\) use properties of logarithms to expand each logarithmic expression as much as possible. Where possible, evaluate logarithmic expressions without using a calculator. $$ \log _{b}\left(x^{2} y\right) $$

In Exercises \(41-70\), use properties of logarithms to condense each logarithmic expression. Write the expression as a single logarithm whose coefficient is \(I .\) Where possible, evaluate logarithmic expressions. $$ 2 \log _{b} x+3 \log _{b} y $$

Describe the change-of-base property and give an example.

In Exercises \(41-70\), use properties of logarithms to condense each logarithmic expression. Write the expression as a single logarithm whose coefficient is \(I .\) Where possible, evaluate logarithmic expressions. $$ 5 \ln x-2 \ln y $$

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