/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 61 Find \(k\) so that \(4 x+3\) is ... [FREE SOLUTION] | 91Ó°ÊÓ

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Find \(k\) so that \(4 x+3\) is a factor of $$20 x^{3}+23 x^{2}-10 x+k$$

Short Answer

Expert verified
The value of \(k\) that makes \(4x+3\) a factor of \(20 x^{3}+23x^{2}-10x+k\) is -13.25. This value is obtained by equating the polynomial to zero for the value of \(x\) that nullifies the factor, and then solving for \(k\).

Step by step solution

01

Solve \(4x+3\) for \(x\)

First, solve the equation \(4x+3=0\) for \(x\) to obtain \(x=-3/4\). Here's the calculation: \(4x+3=0\) Subtraction 3 from both sides gives: \(4x=-3\) Dividing both sides by 4 gives: \(x=-3/4\)
02

Plug \(x=-3/4\) into the polynomial

Next, you need to plug \(x=-3/4\) into the polynomial \(20 x^{3}+23x^{2}-10x+k\) and equate it to zero, since a factor should nullify the polynomial. \(20(-3/4)^3+23(-3/4)^2-10(-3/4)+k=0\)
03

Compute and solve for \(k\)

Simplify the equation to find the value of \(k\) After mathematical manipulation, the equation simplifies to: \(-27+131/4+15/2+k=0\) Simplify further to: \(-27+32.75+7.5+k=0\) Which simplifies to: \(k= -13.25\) \ k is equal to negative 13.25

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