/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 17 Determine the constant of variat... [FREE SOLUTION] | 91Ó°ÊÓ

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Determine the constant of variation for each stated condition. \(W\) varies inversely as \(r,\) and \(W=500\) when \(r=10\)

Short Answer

Expert verified
The constant of variation, \(k\), equals 5000.

Step by step solution

01

Understand inverse proportionality

In an inverse variation, if \(W\) varies inversely as \(r\), this can be expressed algebraically as \(W = \frac{k}{r}\), where \(k\) is a constant.
02

Substitute the given values

Substitute \(W = 500\) and \(r = 10\) into the formula. This gives us the equation \(500 = \frac{k}{10}\).
03

Solve for the constant, \(k\)

To isolate \(k\), simply multiply each side of the equation by \(10\). This gives us \(k = 500 \times 10\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Constant of Variation
In understanding the mechanics of inverse proportion, the concept of the 'constant of variation' plays a pivotal role. Imagine it as the anchor of the relationship between two variables that are connected in such a way that as one increases, the other decreases at a consistent rate. It's the numerical glue that holds the inversely proportional relationship firm.

Consider our exercise example where the variable W is inversely proportional to the variable r. The formula representing this inverse variation is given by W = k / r, where k is our constant of variation. It remains unaltered regardless of the values of W and r. Finding the constant of variation involves substituting known values of W and r and then algebraically solving for k.

To solidify this concept with an example, let's use the provided exercise. We're told that W = 500 when r = 10. Substituting these into the inverse variation formula, we obtain the equation 500 = k / 10. By multiplying each side of the equation by 10, we deduce that k = 5000. This is a clear demonstration of determining the constant of variation within this context.
Proportionality in Algebra
The term 'proportionality' often surfaces in algebra when discussing the direct or inverse relationships between quantities. When we say two variables are directly proportional, increasing one results in a proportional increase in the other and vice versa. Inverse proportionality, the focus of our discussion, is quite the opposite.

In an inverse proportion, such as the one between our variables W and r, as one variable increases, the other decreases–and they do so at rates that are inversely related. This phenomenon can be compared to a seesaw, where the rise of one side directly corresponds with the fall of the other side. For every pair of inversely proportional variables, there exists a constant of variation that maintains their relationship. This interconnection is mathematically beautiful and omnipresent in both natural phenomena and human-engineered systems.

Grasping this concept is critical. It's not enough to recognize the algebraic expression of an inverse relationship; one must understand the underlying principle that governs the interaction of the variables within the realms of proportionality.
Solving Inverse Proportion
When faced with an inverse proportion problem, the strategy for finding a solution is methodical but straightforward. Solving inverse proportion means determining one variable when given the other, based on their established inverse relationship. This is possible because of the reliable presence of the constant of variation.

The process is two-fold: (1) establishing the constant of variation with the provided pairs of variables and (2) using this constant to find unknown variable values. Our earlier example has shown us how to carry out the first step: by substituting the known values of the variables and solving for the constant k.

Following this, if we wish to find a new value for W given a different r, we would simply rearrange our formula to W = k / r and substitute the new r value and our previously determined constant k to solve for W. It's this process that embodies the essence of solving inverse proportions in algebra and is a fundamental tool for a wide variety of mathematical applications, from simple homework problems to complex scientific computations.

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Most popular questions from this chapter

Use everyday language to describe the behavior of a graph near its vertical asymptote if \(f(x) \rightarrow \infty\) as \(x \rightarrow-2^{-}\) and \(f(x) \rightarrow-\infty\) as \(x \rightarrow-2^{+}\).

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