/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 Find the distance between each p... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the distance between each pair of points. If necessary, round answers to two decimals places. $$ (4,1) \text { and }(6,3) $$

Short Answer

Expert verified
The distance between the points (4,1) and (6,3) is approximately 2.83.

Step by step solution

01

Identify the Coordinates

Identify the coordinates of the two points. Here, the points are (4,1) and (6,3). This means that \((x_1, y_1) = (4,1)\) and \((x_2, y_2) = (6,3)\).
02

Apply the Distance Formula

Next, substitute the coordinates into the distance formula: \[d = \sqrt{{(x_2 - x_1)^2 + (y_2 - y_1)^2}}\] This leads to: \[d = \sqrt{{(6 - 4)^2 + (3 - 1)^2}}.\]
03

Simplify the Expression

Then, simplify the expression under the square root: \[d = \sqrt{{(2)^2 + (2)^2}} = \sqrt{{4 + 4}} = \sqrt{{8}}.\]
04

Round to Two Decimal Places

Finally, if necessary, round the final answer to two decimal places. In this case, \(\sqrt{8}\) is approximately 2.83 when rounded to two decimal places.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coordinate Geometry
Coordinate geometry, also known as analytic geometry, is a branch of mathematics that allows us to analyze geometric shapes using algebraic equations by translating them into a coordinate system, usually represented by the x and y axes on a graph. In coordinate geometry, each point in the plane is defined by a pair of numerical coordinates, which are the distances from the point to two fixed perpendicular directed lines, measured in the same unit of length.

When working with coordinate geometry, students learn how to plot points, calculate the slopes of lines, find the equations of lines, and determine distances and areas among other quantities. For example, plotting the points \(4,1\) and \(6,3\) on a graph gives us two locations in the plane. From these, we can visualize the straight line they might form or calculate the distance between them using certain formulas.

This field of mathematics is crucial because it builds a bridge between algebra and geometry, allowing problems to be solved numerically and graphically.
Algebraic Distance Calculation
Algebraic distance calculation is a technique that allows us to determine the precise length between two points in a coordinate plane. It is based on the concept that the distance is the hypotenuse of a right triangle whose legs are the differences between corresponding coordinates of the points. The distance formula, \[d = \sqrt{((x_2 - x_1)^2 + (y_2 - y_1)^2)}\], is rooted in algebra and computes this hypotenuse.

To make this more tangible, let’s consider two points, like \(4,1\) and \(6,3\). In algebraic terms, the difference in x-coordinates is 6 - 4, and the difference in y-coordinates is 3 - 1. Each of these differences represents a side of the right triangle. Applying these differences to the distance formula gives us the hypotenuse – which is the distance between the two points – in a precise algebraic expression. This method is powerful not only for its precision but also because it negates the need for graphing, allowing distances to be calculated with just the coordinates and some basic algebra.
Pythagorean Theorem
The Pythagorean theorem is a fundamental principle in mathematics that states that in a right-angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides. Expressed in a formula, it is \[a^2 + b^2 = c^2\], where 'c' represents the length of the hypotenuse, and 'a' and 'b' represent the lengths of the triangle’s other two sides.

When calculating the distance between two points, such as \(4,1\) and \(6,3\), we can think of the line connecting these points as the hypotenuse of a right triangle. The differences in their x and y coordinates form the lengths of the other sides of this imaginary triangle. Thus, using the Pythagorean theorem, we determine the length of the hypotenuse, which is the distance between the two points. This idea is embedded in the distance formula we use in coordinate geometry, showcasing the seamless integration of geometry and algebra in solving such problems. Understanding and applying the Pythagorean theorem is not only important in geometry and trigonometry but also essential in various fields, including physics, engineering, and computer science.

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Most popular questions from this chapter

The number of lawyers in the United States can be modeled by the function $$ f(x)=\left\\{\begin{array}{ll} 6.5 x+200 & \text { if } 0 \leq x<23 \\ 26.2 x-252 & \text { if } x \geq 23 \end{array}\right. $$ where \(x\) represents the number of years after 1951 and \(f(x)\) represents the number of lawyers, in thousands. In Exercises \(85-88,\) use this function to find and interpret each of the following. $$ f(50) $$

Describe how to write the equation of a line if two points along the line are known.

What must be done to a function's equation so that its graph is reflected about the \(y\) -axis?

Consult an almanac, newspaper, magazine, or the Internet to find data displayed in a graph.$ Using the two graphs that group members find most interesting, introduce two functions that are related to the graphs. Then write and solve a problem involving function subtraction for each selected graph.

Almanacs, newspapers, magazines, and the Internet contain bar graphs and line graphs that describe how things are changing over time. For example, the graphs in Exercises \(79-82\) show how various phenomena are changing over time. Find a bar or line graph showing yearly changes that you find intriguing. Describe to the group what interests you about this data. The group should select their two favorite graphs. For each graph selected: a. Rewrite the data so that they are presented as a relation in the form of a set of ordered pairs. b. Determine whether the relation in part (a) is a function. Explain why the relation is a function, or why it is not.

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