Chapter 1: Problem 98
Solve each equation in Exercises 73-98 by the method of your choice. $$\frac{3}{x-3}+\frac{5}{x-4}=\frac{x^{2}-20}{x^{2}-7 x+12}$$
Short Answer
Expert verified
The given equation has no solution in the real number set.
Step by step solution
01
Simplification
Rewrite the equation \(\frac{3}{x-3}+\frac{5}{x-4}=\frac{x^{2}-20}{x^{2}-7 x+12}\) in the form \(\frac{A}{x-3}+\frac{B}{x-4}=\frac{C}{(x-3)(x-4)}\), where \(A\), \(B\), and \(C\) are expressions to be determined. Multiply throughout by \((x-3)(x-4)\) to clear the fractions. This gives you \(3(x-4)+5(x-3)=x^{2}-20\). After simplification, this becomes \(8x-27=x^{2}-20\).
02
Solving the quadratic equation
Rearrange the equation from Step 1 and set it to zero: \(x^{2}-8x+47=0\). Now the equation becomes a quadratic equation, and it can be solved by the quadratic formula \(x=\frac{-b±\sqrt{b^2-4ac}}{2a}\). The coefficients from our equation are \(a=1\), \(b=-8\), and \(c=47\). Substituting these values into the formula gives the roots of the equation as \(x_{1,2}=\frac{8±\sqrt{(-8)^{2}-4*1*47}}{2*1}\).
03
Calculation and verification
The numbers under the square root in the formula \(x_{1,2}\) from Step 2 are imaginary numbers because the discriminant \(b^{2}-4ac<0\). Since we are dealing with real numbers, there will be no solutions for the equation.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
The quadratic formula is a powerful tool for solving quadratic equations, which are equations of the form \( ax^2 + bx + c = 0 \). It provides a straightforward way to find the 'roots' or solutions of the quadratic equation. The formula is:
- \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
- \(a\), \(b\), and \(c\) are coefficients of the terms in the equation.
- \(\pm\) indicates two solutions: one for adding and one for subtracting the square root.
- The term under the square root, \( b^2 - 4ac \), is called the "discriminant" and plays a crucial role in determining the nature of the roots.
Discriminant
The discriminant of a quadratic equation \( ax^2 + bx + c = 0 \) is the part \( b^2 - 4ac \) found under the square root in the quadratic formula. It provides critical information about the nature of the roots of the equation:
- If the discriminant is positive, \(b^2 - 4ac > 0\), the quadratic equation has two distinct real roots.
- If it is zero, \(b^2 - 4ac = 0\), there is exactly one real root, also known as a repeated or double root.
- If the discriminant is negative, \(b^2 - 4ac < 0\), the equation has no real solutions, but rather two complex conjugate roots, involving imaginary numbers.
Imaginary Numbers
Imaginary numbers are a fascinating component of mathematics that come into play when we encounter square roots of negative numbers. Typically, the square root of a negative number cannot be computed within the realm of real numbers. Therefore, we introduce the imaginary unit, denoted by \( i \), where \( i = \sqrt{-1} \).
- This allows us to express roots of negative numbers. For example, \( \sqrt{-4} = 2i \).
- Once we include imaginary numbers, we expand our number system to include complex numbers, which have a 'real' part and an 'imaginary' part. A typical complex number looks like \( a + bi \), where \( a \) is the real part and \( b \) is the imaginary part.
Simplification of Rational Expressions
Simplification of rational expressions is a crucial skill in algebra that makes handling fractions with polynomials easier and more manageable. A rational expression is a fraction in which both the numerator and the denominator are polynomials. Simplifying these involves:
- Finding and eliminating common factors from the numerator and the denominator.
- Rewriting complex fractions in simpler terms, usually through a common denominator or polynomial division.