Chapter 1: Problem 90
Solve each equation in Exercises 73-98 by the method of your choice. \(x^{2}-4 x+29=0\)
Short Answer
Expert verified
The solutions to the equation \(x^{2}-4x+29=0\) are \(x = 2 + 5i\) and \(x = 2 - 5i\).
Step by step solution
01
Express the equation in standard form
The quadratic equation is already in standard form: \(ax^{2} + bx + c = 0\). In our case, \(a = 1\), \(b = -4\) and \(c = 29\).
02
Calculate the discriminant
We would now find the discriminant of the equation, which is given by \(b^{2}-4ac\). Substituting the values we have: \((-4)^{2}-4(1)(29) = 16 - 116 = -100.\)
03
Evaluate the roots
Substitute \(a\), \(b\), and \(c\) into the quadratic formula to find the solution. The formula gives us \(x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}\). Substituting the values of \(a\), \(b\) and \(c\), we get \(x = \frac{-(-4) \pm \sqrt{-100}}{2*1} = \frac{4 \pm \sqrt{-100}}{2}\).\nSince the discriminant is negative, we have complex roots. Recalling that \(\sqrt{-1} = i\), we can rewrite \(\sqrt{-100}\) as \(10i\). Therefore, we have \(x = \frac{4 \pm 10i}{2} = 2 \pm 5i\).
04
Expressing the final solution
The solutions are both complex numbers. Thus, the equation \(x^{2}-4x+29=0\) has two complex solutions: \(x = 2 + 5i\) and \(x = 2 - 5i\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Complex Numbers
Complex numbers are essential when dealing with equations that have negative discriminants. A complex number is often represented as a combination of a real part and an imaginary part, typically given in the form \(a + bi\). Here, \(a\) is the real component, and \(b\) is the imaginary component multiplied by the imaginary unit \(i\), where \(i\) represents the square root of \(-1\).
- Imaginary Part: It involves the elusive mathematical construct \(i = \sqrt{-1}\). When a number has a negative inside the square root, the result is imaginary.
- Real Part: The real component, such as \(a\) in \(a + bi\), is simply a conventional number that we encounter in everyday mathematics.
Quadratic Formula
The quadratic formula is a powerful tool that solves any quadratic equation of the form \(ax^2 + bx + c = 0\). This formula helps find the roots of the quadratic equation and is especially useful when factoring is not straightforward. The formula is given by:
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
- The symbol \(\pm\) indicates that there are usually two solutions.
- The values of \(a\), \(b\), and \(c\) are known coefficients from the quadratic equation.
- The numerical expression under the square root, \(b^2 - 4ac\), is called the discriminant and determines the nature of the roots.
Discriminant
The discriminant is a pivotal element in determining the nature of the roots of a quadratic equation. Denoted by \(D\), the discriminant is calculated using the expression \(b^2 - 4ac\) derived from the coefficients of the equation: \(ax^2 + bx + c = 0\). The discriminant not only reveals the type of solutions but also their number.
- If \(D > 0\): The quadratic equation has two distinct real roots.
- If \(D = 0\): The equation has exactly one real root, or it is said to have a repeated root.
- If \(D < 0\): The equation has two complex roots, which are conjugates of each other.
Standard Form of a Quadratic Equation
The standard form of a quadratic equation is crucial in understanding and solving quadratic problems. It appears as \(ax^2 + bx + c = 0\). Here, \(x\) is the variable, and \(a\), \(b\), and \(c\) are coefficients with specific roles in the equation:
- \(a\): The coefficient of \(x^2\) and must be non-zero. It determines the parabola's "width" or "narrowness" when plotted.
- \(b\): The coefficient of \(x\). It helps in determining the direction the parabola shifts along the x-axis.
- \(c\): The constant term. It affects the vertical shift of the parabola along the y-axis.