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Chapter 1: Problem 6

Plot the given point in a rectangular coordinate system. $$(-4,-2)$$

Short Answer

Expert verified
The point (-4, -2) can be plotted on the 2-dimensional coordinate system by moving 4 units to the left from the origin (for x-coordinate -4) and 2 units downwards (for y-coordinate -2).

Step by step solution

01

Identify X and Y Coordinates

The point specified is (-4, -2). Here, -4 is the x-coordinate (horizontal placement) and -2 is the y-coordinate (vertical placement).
02

Draw the Coordinate System

Next, draw the Cartesian coordinate system which is essentially two perpendicular lines intersecting at a point called Origin. The horizontal line is called 'x-axis' and the vertical line is 'y-axis'.
03

Locate the X Coordinate

Locate -4 on the x-axis. Since it's a negative number, move 4 units to the left from the origin.
04

Locate the Y Coordinate

Now, from point -4 on the x-axis, locate -2 on the y-axis. Since it's negative, move 2 units downwards.
05

Plot the Point

Finally, mark the point (-4, -2) where the x and y coordinates meet.

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Most popular questions from this chapter

Solve each rational inequality in Exercises \(29-48,\) and graph the solution set on a real number line. Express each solution set in interval notation. $$ \frac{x-2}{x+2} \leq 2 $$

Solve each quadratic inequality in Exercises \(1-28\) and graph the solution set on a real number line. Express each solution set in interval notation. $$ -x^{2}+2 x \geq 0 $$

In Exercises \(69-72,\) use inspection to describe each inequality's solution set. Do not solve any of the inequalities. $$ (x-2)^{2} \leq 0 $$

In Exercises \(9-20,\) find each product and write the result in standard form. $$(-4-8 i)(3+9 i)$$

In Exercises \(29-44,\) perform the indicated operations and write the result in standard form. $$(-2+\sqrt{-4})^{2}$$
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