/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 122 Solve each inequality using a gr... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Solve each inequality using a graphing utility. Graph each side separately. Then determine the values of \(x\) for which the graph on the left side lies above the graph on the right side. $$-2(x+4)>6 x+16$$

Short Answer

Expert verified
The exact solution will depend on how the functions are graphed and may need verification. This is a visual approach, and the solution lies in the interval of x-values where the graph of \( y1 = -2(x+4) \) is above the graph of \( y2 = 6x+16 \).

Step by step solution

01

Rewrite

Rewrite the inequality \( -2(x+4)>6x+16 \) into two equations to visually graph them. They are \( y1 = -2(x+4) \) and \( y2 = 6x+16 \)
02

Graph Equations

Plot the functions \( y1 = -2(x+4) \) and \( y2 = 6x+16 \) on a graphing utility. It is important to see the parts of two graphs in relation to each other.
03

Determine Solution

The solution to the inequality is the interval of x-values where the graph of \( y1 = -2(x+4) \) lies above the graph of \( y2 = 6x+16 \). Carefully observe where the first function is higher than the second function to find the interval of solution.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.