Chapter 9: Problem 27
For the following exercises, use the Binomial Theorem to write the first three terms of each binomial. $$ (3 a+b)^{20} $$
Short Answer
Expert verified
First three terms: \((3a)^{20}, 20 \cdot 3^{19} a^{19} b, 190 \cdot 3^{18} a^{18} b^2\).
Step by step solution
01
Identify the Binomial
The binomial expression given is \((3a + b)^{20}\). This means we are looking to expand the expression \((3a + b)\) raised to the 20th power.
02
Apply the Binomial Theorem Formula
The Binomial Theorem states that \((x + y)^n = \sum_{k=0}^{n} \binom{n}{k} x^{n-k} y^k\). Here, \(x = 3a\), \(y = b\), and \(n = 20\). We're tasked with finding the first three terms.
03
Calculate the First Term
For the first term, set \(k = 0\). The first term is \(\binom{20}{0} (3a)^{20-0} b^0 = 1 \cdot (3a)^{20} = (3a)^{20}\). Calculate \((3a)^{20} = 3^{20} a^{20}\). The calculation of \(3^{20}\) would be a huge number but should be left in terms of powers in this context.
04
Calculate the Second Term
For the second term, set \(k = 1\). Calculate: \(\binom{20}{1} (3a)^{19} b^1\). We have \(\binom{20}{1} = 20\), leading to \(20 \cdot (3a)^{19} \cdot b = 20 \cdot 3^{19} a^{19} b\).
05
Calculate the Third Term
For the third term, set \(k = 2\). Calculate: \(\binom{20}{2} (3a)^{18} b^2\). We get \(\binom{20}{2} = \frac{20 \cdot 19}{2} = 190\). This results in \(190 \cdot (3a)^{18} \cdot b^2 = 190 \cdot 3^{18} a^{18} b^2\).
06
Assemble the First Three Terms
Combine the calculated terms: 1. \((3a)^{20}\),2. \(20 \cdot 3^{19} a^{19} b\),3. \(190 \cdot 3^{18} a^{18} b^2\).These are the first three terms of the binomial expansion.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Binomial Expansion
The binomial expansion is a handy mathematical tool to express a binomial expression raised to a power as a series or sum of terms. The Binomial Theorem is key to binomial expansion. It offers a formula to expand such expressions using combinations from combinatorics. The Binomial Theorem is defined as \[ (x + y)^n = \sum_{k=0}^{n} \binom{n}{k} x^{n-k} y^k \] In this formula,
- \(n\) is the power to which the binomial is raised,
- \(\binom{n}{k}\) is a binomial coefficient that represents the number of ways to choose \(k\) elements from \(n\),
- \(x\) and \(y\) are the terms of the binomial expression.
Combinatorics
Combinatorics is a fascinating area of mathematics focused on counting, arranging, and finding patterns. When it comes to binomial expansion, combinatorics provides us with binomial coefficients, denoted as \( \binom{n}{k} \), which are central to the Binomial Theorem.Binomial coefficients can be interpreted in several ways:
- They tell us how many ways we can choose \(k\) elements from a set of \(n\) elements.
- Mathematically, \(\binom{n}{k} = \frac{n!}{k!(n-k)!} \), where \(n!\) represents the factorial of \(n\).
Polynomials
Polynomials are expressions constructed from variables and constants, using operations such as addition, subtraction, multiplication, and non-negative integer exponents. Binomials, which have just two terms, are a special kind of polynomial.When you expand a binomial expression like \((3a + b)^{20}\) using the Binomial Theorem, you transform it into a polynomial that typically has many more terms. Each term in this expanded polynomial represents a different combination of powers of \(3a\) and \(b\), multiplied by a specific binomial coefficient.Key points to remember:
- Every term in the expanded polynomial represents a different combination of the constituent elements with a binomial coefficient.
- Using the Binomial Theorem translates a simple two-term binomial into a complex polynomial while preserving the properties of polynomials.