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For the following exercises, identify the conic with a focus at the origin, and then give the directrix and eccentricity. $$ r=\frac{6}{1-2 \cos \theta} $$

Short Answer

Expert verified
The conic is a hyperbola with eccentricity 2 and the directrix is \(x = -3\).

Step by step solution

01

Identify the type of conic

The given polar equation is in the form \( r = \frac{ed}{1 + e\cos\theta} \) or \( r = \frac{ed}{1 - e\cos\theta} \), which are the general forms for conics. The negative sign in front of the cosine (\(-2\cos\theta\)) suggests the format matches the equation \( r = \frac{ed}{1 - e\cos\theta} \), indicating it is a conic with a focus at the origin and a directrix perpendicular to the x-axis (horizontal).
02

Determine the eccentricity

In the equation \( r = \frac{6}{1 - 2\cos\theta} \), compare it with the standard form \( r = \frac{ed}{1 - e\cos\theta} \). The numeral 2 in front of \(\cos\theta\) represents the eccentricity \(e\). Hence, \(e = 2\).
03

Identify the type of conic from eccentricity

The eccentricity determines the type of conic:- Ellipse if \(0 < e < 1\)- Parabola if \(e = 1\)- Hyperbola if \(e > 1\)Since \(e = 2\), which is greater than 1, the conic is a hyperbola.
04

Determine the directrix

For the equation in the form \( r = \frac{ed}{1 - e\cos\theta} \), the numerator 6 is \(ed\). Since \(e = 2\), set up the equation: \[ed = 6 \2d = 6\d = 3\].Therefore, the directrix of the hyperbola is \(x = -3\), since it is a horizontal directrix (because of \(\cos\theta\)).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polar Coordinates
Polar coordinates offer an alternative to Cartesian coordinates for plotting points in a plane. They consist of a pair, \(r, \ heta\), where \r\ is the distance from the origin and \theta\ is the angle measured from the positive x-axis. This system is particularly useful for describing curves and shapes centered around a point or involving angles. Conic sections often have simpler equations in polar coordinates, which is why they're commonly used in these scenarios. In the exercise, we see a conic expressed in polar form as \(r = \ rac{6}{1 - 2\cos\theta}\). This form allows us to immediately recognize the type of conic and important characteristics like eccentricity and directrix.
Eccentricity
Eccentricity is a critical parameter in defining the shape of conic sections. It is denoted by \e\ and tells us how much a conic section deviates from being circular. The value of eccentricity determines the nature of the conic:
  • If \(0 < e < 1\), the conic is an ellipse.
  • If \(e = 1\), it is a parabola.
  • If \(e > 1\), it is a hyperbola.
In our problem, with the equation \(r = \ rac{6}{1 - 2\cos\theta}\), the eccentricity is found to be \e = 2\. Since \(e > 1\), the given conic is a hyperbola, which naturally follows from its definition as having two separate branches.
Directrix
The directrix is a line related to a conic section that helps maintain its geometric properties with respect to a focus. Each type of conic section - ellipse, parabola, or hyperbola - uses the directrix in its definition. The relationship between the focus, directrix, and eccentricity is crucial to understanding conics.For a hyperbola described in polar coordinates by \(r = \ rac{ed}{1 - e\cos\theta}\), the term \(ed\) represents the product of eccentricity and the distance from the pole to the directrix. From the given problem, this product is 6, given the equation is \(r = \ rac{6}{1 - 2\cos\theta}\). With \e = 2\, solving \(2d = 6\) gives us \d = 3\. Therefore, the directrix is located at \x = -3\.
Hyperbola
A hyperbola is a type of conic section that is defined as the locus of all points where the difference of distances from two fixed points, known as foci, is constant. Unlike an ellipse, a hyperbola forms two separate curves called branches. It can open horizontally or vertically in the plane. In polar coordinates, the general equation of a hyperbola is given as \(r = \ rac{ed}{1 \pm e\cos\theta}\) or \(r = \ rac{ed}{1 \pm e\sin\theta}\).In this exercise, the hyperbola has a polar equation \(r = \ rac{6}{1 - 2\cos\theta}\), where the negative cosine indicates a horizontal directrix, which results in a horizontally opening hyperbola. Key features that characterize a hyperbola include its branches, asymptotes, foci, and of course, its eccentricity which, in this case, confirms the hyperbola with \(e = 2\).

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