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In the following exercises, show that matrix \(A\) is the inverse of matrix \(B\) $$A=\left[\begin{array}{ll}{4} & {5} \\ {7} & {0}\end{array}\right], B=\left[\begin{array}{ll}{0} & {\frac{1}{7}} \\ {\frac{1}{5}} & {-\frac{4}{35}}\end{array}\right]$$

Short Answer

Expert verified
Matrix A is the inverse of Matrix B because both AB and BA equal the identity matrix.

Step by step solution

01

Define Inverse Matrix Multiplication

To show that matrix \(A\) is the inverse of matrix \(B\), we need to verify that the product of \(A\) and \(B\) results in the identity matrix. This is symbolically expressed as: \[AB = I\] and \[BA = I\]where \(I\) is the identity matrix of the same size as \(A\) and \(B\).
02

Compute Matrix Product AB

Compute the product \(AB\): Given:\[A = \begin{bmatrix} 4 & 5 \ 7 & 0 \end{bmatrix}, B = \begin{bmatrix} 0 & \frac{1}{7} \ \frac{1}{5} & -\frac{4}{35} \end{bmatrix}\]The product is calculated as:\[AB = \begin{bmatrix} 4 \times 0 + 5 \times \frac{1}{5} & 4 \times \frac{1}{7} + 5 \times -\frac{4}{35} \ 7 \times 0 + 0 \times \frac{1}{5} & 7 \times \frac{1}{7} + 0 \times -\frac{4}{35} \end{bmatrix}\]\[ = \begin{bmatrix} 0 + 1 & \frac{4}{7} - \frac{20}{35} \ 0 & 1 \end{bmatrix} = \begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix}\]This is the identity matrix.
03

Compute Matrix Product BA

Compute the product \(BA\):Using:\[A = \begin{bmatrix} 4 & 5 \ 7 & 0 \end{bmatrix}, B = \begin{bmatrix} 0 & \frac{1}{7} \ \frac{1}{5} & -\frac{4}{35} \end{bmatrix}\]We calculate the product:\[BA = \begin{bmatrix} 0 \times 4 + \frac{1}{7} \times 7 & 0 \times 5 + \frac{1}{7} \times 0 \ \frac{1}{5} \times 4 + -\frac{4}{35} \times 7 & \frac{1}{5} \times 5 + -\frac{4}{35} \times 0 \end{bmatrix}\]\[ = \begin{bmatrix} 1 & 0 \ \frac{4}{5} - \frac{28}{35} & 1 \end{bmatrix}\]\[ = \begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix}\]Again, this is the identity matrix.
04

Conclusion

Since both products \(AB\) and \(BA\) yield the identity matrix, it confirms that matrix \(A\) is indeed the inverse of matrix \(B\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Matrix Multiplication
Matrix multiplication is a fundamental operation where two matrices are multiplied together to produce a new matrix. This operation is not as straightforward as multiplying two numbers; it requires a specific procedure. To multiply two matrices, the number of columns in the first matrix must equal the number of rows in the second matrix.
The resulting matrix has dimensions of the number of rows of the first matrix by the number of columns of the second matrix.
  • Each element in the resulting matrix is calculated by taking the dot product of the corresponding row from the first matrix and the column from the second matrix.
  • For example, if you have a matrix \( A \), which is 2x2, and another matrix \( B \), which is also 2x2, the product \( AB \) will also be a 2x2 matrix.
In our exercise, the multiplication of matrices \( A = \begin{bmatrix} 4 & 5 \ 7 & 0 \end{bmatrix} \) and \( B = \begin{bmatrix} 0 & \frac{1}{7} \ \frac{1}{5} & -\frac{4}{35} \end{bmatrix} \) is calculated by multiplying the corresponding rows and columns as described. Remember, matrix multiplication is not commutative, meaning \( AB eq BA \) generally, which is why we needed to show both \( AB = I \) and \( BA = I \) in the steps.
Identity Matrix
An identity matrix is a special kind of matrix that acts like the number 1 in matrix operations. When you multiply any matrix by an identity matrix, the result is the original matrix itself.
This "do nothing" feature makes it crucial when finding the inverse of a matrix.
  • The identity matrix is always a square matrix, meaning it has the same number of rows and columns.
  • It contains 1s on the main diagonal (from the top-left to the bottom-right) and 0s elsewhere. For a 2x2 matrix, the identity matrix \( I \) looks like this: \( \begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix} \).
In our exercise, we verified that matrix \( A \) is the inverse of matrix \( B \) because the products \( AB \) and \( BA \) both equaled the identity matrix \( \begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix} \). This demonstrates the defining quality of inverse matrices.
Matrix Operations
Matrix operations encompass a variety of actions you can perform with matrices. Besides multiplication and inverses, these include addition, subtraction, and scalar multiplication. Each operation has its own process and set of rules.
Matrix inversion is particularly important in linear algebra. It involves finding another matrix (the inverse) such that when it is multiplied by the original, it yields the identity matrix.
Not all matrices have inverses; a matrix must be square and have a non-zero determinant to possess an inverse.
  • Addition and subtraction require two matrices of the same dimensions. Each element is added or subtracted from its corresponding element in the other matrix.
  • Scalar multiplication involves multiplying every element by a constant value (or scalar).
  • Matrix multiplication, as discussed earlier, requires matching the inner dimensions of the matrices involved.
Understanding these operations is essential for solving more complex problems in mathematics and applied fields, like engineering and computer science. In this particular exercise, our focus is on matrix multiplication and the properties of inverse matrices.

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Most popular questions from this chapter

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